X Rays and the Ordering of the Elements — Question 6

Section 40-9 · Physics pages 6742–6743

Question 6 An electron tube can show a continuum without exciting a selected characteristic line A target has K binding energy BK = 18.0 keV and Kα photon energy 15.5 keV. Electrons are accelerated from rest through 16.0 kV. Assume K vacancies must be made by these incident electrons. Ke = 16.0 keV BK = 18.0 keV ∆E Schematic; labels, not drawing lengths, specify the data. (a) Determine whether Kα emission is accessible even though the incident energy exceeds the line energy. (b) Find the continuum cutoffat 16.0 kV and the minimum threshold voltage for direct K-vacancy production.
Show solutionHide solution
Question 6 - Solution An electron tube can show a continuum without exciting a selected characteristic line Ke = 16.0 keV BK = 18.0 keV ∆E (a) Method and calculation Ke = 16.0 keV < BK = 18.0 keV. K-vacancy creation is energetically forbidden in this model . (b) Interpretation and further calculation λmin = 1.240/16.0 = .0775 nm . eVth = BK ⇒Vth = 18.0 kV . Physical check The incident electron must first create a core hole, whose threshold exceeds the eventual line energy. An energetic threshold does not imply a large production rate exactly at threshold.

Question 6

An electron tube can show a continuum without exciting a selected characteristic line

A target has K binding energy BK=18.0keVB_K=18.0\,\mathrm{keV} and KαK_\alpha photon energy 15.5keV15.5\,\mathrm{keV}. Electrons are accelerated from rest through 16.0 kV. Assume K vacancies must be made by these incident electrons.

Diagram shown in the original SVG worksheet.

  1. Determine whether KαK_\alpha emission is accessible even though the incident energy exceeds the line energy.

  2. Find the continuum cutoff at 16.0 kV and the minimum threshold voltage for direct K-vacancy production.

Question 6 - Solution

An electron tube can show a continuum without exciting a selected characteristic line

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Ke=16.0keV<BK=18.0keV.K_e=16.0\,\mathrm{keV}<B_K=18.0\,\mathrm{keV}.K-vacancy creation is energetically forbidden in this model.\boxed{\text{K-vacancy creation is energetically forbidden in this model}}.

(b) Interpretation and further calculation

λmin=1.240/16.0=.0775nm.\boxed{\lambda_{\min}=1.240/16.0=.0775\,\mathrm{nm}}.eVth=BK⇒Vth=18.0kV.eV_{\mathrm{th}}=B_K\Rightarrow\boxed{V_{\mathrm{th}}=18.0\,\mathrm{kV}}.

Physical check

The incident electron must first create a core hole, whose threshold exceeds the eventual line energy. An energetic threshold does not imply a large production rate exactly at threshold.