Building the Periodic Table — Question 8

Section 40-8 · Physics pages 6726–6727

Question 8 Spin-only magnetic moments vary systematically across a d subshell Use Hund filling for a degenerate d subshell and the spin-only moment µeff= gsµB √ S(S + 1) with gs = 2. Neglect orbital magnetism and spin-orbit corrections. Schematic; labels, not drawing lengths, specify the data. (a) For occupancies d3 and d8, find the number of unpaired electrons and S. (b) Calculate their effective moments and their ratio.
Show solutionHide solution
Question 8 - Solution Spin-only magnetic moments vary systematically across a d subshell (a) Method and calculation d3 : Nu = 3, S = 3/2 ; d8 : Nu = 10 −8 = 2, S = 1 . µeff= 2µB √ (Nu/2)(Nu/2 + 1) = µB √ Nu(Nu + 2). (b) Interpretation and further calculation µd3 = √ 15µB = 3.873µB, µd8 = √ 8µB = 2.828µB . µd3/µd8 = √ 15/8 = 1.369 . Physical check The effective moment magnitude differs from the largest projection gS times the Bohr magneton. The spin-only approximation is appropriate only when orbital contributions are negligible.

Question 8

Spin-only magnetic moments vary systematically across a d subshell

Use Hund filling for a degenerate d subshell and the spin-only moment μeff=gsμBS(S+1)\mu_{\mathrm{eff}}=g_s\mu_B\sqrt{S(S+1)} with gs=2g_s=2. Neglect orbital magnetism and spin-orbit corrections.

Diagram shown in the original SVG worksheet.

  1. For occupancies d3d^3 and d8d^8, find the number of unpaired electrons and S.

  2. Calculate their effective moments and their ratio.

Question 8 - Solution

Spin-only magnetic moments vary systematically across a d subshell

Diagram shown in the original SVG worksheet.

(a) Method and calculation

d3:Nu=3,S=3/2;d8:Nu=10−8=2,S=1.d^3:\ N_u=3,\ \boxed{S=3/2};\qquad d^8:\ N_u=10-8=2,\ \boxed{S=1}.μeff=2μB(Nu/2)(Nu/2+1)=μBNu(Nu+2).\mu_{\mathrm{eff}}=2\mu_B\sqrt{(N_u/2)(N_u/2+1)}=\mu_B\sqrt{N_u(N_u+2)}.

(b) Interpretation and further calculation

μd3=15μB=3.873μB,μd8=8μB=2.828μB.\boxed{\mu_{d^3}=\sqrt{15}\mu_B=3.873\mu_B,\quad\mu_{d^8}=\sqrt8\mu_B=2.828\mu_B}.μd3/μd8=15/8=1.369.\boxed{\mu_{d^3}/\mu_{d^8}=\sqrt{15/8}=1.369}.

Physical check

The effective moment magnitude differs from the largest projection gS times the Bohr magneton. The spin-only approximation is appropriate only when orbital contributions are negligible.