Multiple Electrons in Rectangular Traps — Question 3

Section 40-7 · Physics pages 6696–6697

Question 3 Full spin polarization increases the confinement energy Six noninteracting electrons occupy a one-dimensional well with energies En = ϵn2. Compare the lowest orbital energy with unrestricted spins to the lowest energy when all six spins are forced parallel. Omit the energy needed to produce the polarization. Schematic; labels, not drawing lengths, specify the data. (a) Find the two occupied-level patterns and energies. (b) Find the energy increase and the ratio of highest occupied energies.
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Question 3 - Solution Full spin polarization increases the confinement energy (a) Method and calculation Unrestricted: n = 1, 2, 3 twice ⇒Eu = 2ϵ(1 + 4 + 9) = 28ϵ . Parallel: n = 1, . . . , 6 once ⇒Ep = ϵ(1 + 4 + 9 + 16 + 25 + 36) = 91ϵ . (b) Interpretation and further calculation Ep −Eu = 63ϵ . Ehighest,p/Ehighest,u = 36/9 = 4 . Physical check Parallel spin removes the second spin slot in each spatial orbital. The increase arises from exclusion and confinement even without an interelectron repulsive potential.

Question 3

Full spin polarization increases the confinement energy

Six noninteracting electrons occupy a one-dimensional well with energies En=ϵn2E_n=\epsilon n^2. Compare the lowest orbital energy with unrestricted spins to the lowest energy when all six spins are forced parallel. Omit the energy needed to produce the polarization.

Diagram shown in the original SVG worksheet.

  1. Find the two occupied-level patterns and energies.

  2. Find the energy increase and the ratio of highest occupied energies.

Question 3 - Solution

Full spin polarization increases the confinement energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Unrestricted: n=1,2,3 twice⇒Eu=2ϵ(1+4+9)=28ϵ.\text{Unrestricted: }n=1,2,3\text{ twice}\Rightarrow\boxed{E_u=2\epsilon(1+4+9)=28\epsilon}.Parallel: n=1,…,6 once⇒Ep=ϵ(1+4+9+16+25+36)=91ϵ.\text{Parallel: }n=1,\ldots,6\text{ once}\Rightarrow\boxed{E_p=\epsilon(1+4+9+16+25+36)=91\epsilon}.

(b) Interpretation and further calculation

Ep−Eu=63ϵ.\boxed{E_p-E_u=63\epsilon}.Ehighest,p/Ehighest,u=36/9=4.\boxed{E_{{\mathrm{highest}},p}/E_{{\mathrm{highest}},u}=36/9=4}.

Physical check

Parallel spin removes the second spin slot in each spatial orbital. The increase arises from exclusion and confinement even without an interelectron repulsive potential.