Magnetic Resonance — Question 8

Section 40-5 · Physics pages 6666–6667

Question 8 A static frequency offset is refocused by a spin echo After an ideal transverse preparation, a spin has rotating-frame coherence c(0) = 1 and constant offset δ. Free evolution gives c(t) = e−iδtc(0). At t = τ, an ideal pulse conjugates c. Irreversible decay contributes e−t/T2. t π pulse τ 2τ Schematic; labels, not drawing lengths, specify the data. (a) Find the offset-dependent phase for t > τ and the echo time. (b) If the echo amplitude at 2τ = .120 s is half its initial value, infer T2.
Show solutionHide solution
Question 8 - Solution A static frequency offset is refocused by a spin echo t π pulse τ 2τ (a) Method and calculation c(τ −) = e−iδτ, c(τ +) = e+iδτ. c(t) ∝e−iδ(t−τ)e+iδτ = e−iδ(t−2τ) ⇒techo = 2τ . (b) Interpretation and further calculation Mecho/M(0) = e−2τ/T2 = 1/2. T2 = .120/ ln 2 = .1731 s . Physical check An ideal echo refocuses static offsets, but not the irreversible transverse decay represented by T2. Time-dependent noise may not be fully refocused.

Question 8

A static frequency offset is refocused by a spin echo

After an ideal transverse preparation, a spin has rotating-frame coherence c(0)=1c(0)=1 and constant offset δ\delta. Free evolution gives c(t)=e−iδtc(0)c(t)=e^{-i\delta t}c(0). At t=τt=\tau, an ideal pulse conjugates c. Irreversible decay contributes e−t/T2e^{-t/T_2}.

Diagram shown in the original SVG worksheet.

  1. Find the offset-dependent phase for t>τt>\tau and the echo time.

  2. If the echo amplitude at 2τ=.120s2\tau=.120\,\mathrm s is half its initial value, infer T2T_2.

Question 8 - Solution

A static frequency offset is refocused by a spin echo

Diagram shown in the original SVG worksheet.

(a) Method and calculation

c(τ−)=e−iδτ,c(τ+)=e+iδτ.c(\tau^-)=e^{-i\delta\tau},\quad c(\tau^+)=e^{+i\delta\tau}.c(t)∝e−iδ(t−τ)e+iδτ=e−iδ(t−2τ)⇒techo=2τ.c(t)\propto e^{-i\delta(t-\tau)}e^{+i\delta\tau}=e^{-i\delta(t-2\tau)}\Rightarrow\boxed{t_{\mathrm{echo}}=2\tau}.

(b) Interpretation and further calculation

Mecho/M(0)=e−2τ/T2=1/2.M_{\mathrm{echo}}/M(0)=e^{-2\tau/T_2}=1/2.T2=.120/ln⁡2=.1731s.\boxed{T_2=.120/\ln2=.1731\,\mathrm s}.

Physical check

An ideal echo refocuses static offsets, but not the irreversible transverse decay represented by T2. Time-dependent noise may not be fully refocused.