Angular Momenta and Magnetic Dipole Moments — Question 5

Section 40-3 · Physics pages 6620–6621

Question 5 Adding orbital and spin angular momenta redistributes a fixed state count An electron has l = 2 and s = 1/2. Angular-momentum addition permits j = |l −s|, |l −s| + 1, . . . , l + s, with 2j + 1 projections for each j. l = 2 ⊗s = 1/2 j = 5/2 j = 3/2 Schematic; labels, not drawing lengths, specify the data. (a) Find the possible j values and their multiplicities. (b) Compare the total coupled-basis dimension with the uncoupled product-basis dimension.
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Question 5 - Solution Adding orbital and spin angular momenta redistributes a fixed state count l = 2 ⊗s = 1/2 j = 5/2 j = 3/2 (a) Method and calculation j = 3/2, 5/2 . g3/2 = 4, g5/2 = 6 . (b) Interpretation and further calculation dcoupled = 4 + 6 = 10 . dproduct = (2l + 1)(2s + 1) = 5(2) = 10 . Physical check Changing from separate orbital and spin projections to total angular momentum changes the basis, not the number of physical states.

Question 5

Adding orbital and spin angular momenta redistributes a fixed state count

An electron has l=2l=2 and s=1/2s=1/2. Angular-momentum addition permits j=|l−s|,|l−s|+1,…,l+sj=|l-s|,|l-s|+1,\ldots,l+s, with 2j+12j+1 projections for each j.

Diagram shown in the original SVG worksheet.

  1. Find the possible j values and their multiplicities.

  2. Compare the total coupled-basis dimension with the uncoupled product-basis dimension.

Question 5 - Solution

Adding orbital and spin angular momenta redistributes a fixed state count

Diagram shown in the original SVG worksheet.

(a) Method and calculation

j=3/2,5/2.\boxed{j=3/2,\ 5/2}.g3/2=4,g5/2=6.\boxed{g_{3/2}=4,\quad g_{5/2}=6}.

(b) Interpretation and further calculation

dcoupled=4+6=10.d_{\mathrm{coupled}}=4+6=\boxed{10}.dproduct=(2l+1)(2s+1)=5(2)=10.d_{\mathrm{product}}=(2l+1)(2s+1)=5(2)=\boxed{10}.

Physical check

Changing from separate orbital and spin projections to total angular momentum changes the basis, not the number of physical states.