Angular Momenta and Magnetic Dipole Moments — Question 1

Section 40-3 · Physics pages 6612–6613

Question 1 The sign of an orbital magnetic moment follows the electron charge A classical circular electron orbit has radius r and speed v. Use charge −e, electron mass m, current magnitude I = e/T, and magnetic-moment magnitude Iπr2. r L µL Schematic; labels, not drawing lengths, specify the data. (a) Derive the vector relation between orbital magnetic moment and angular momentum. (b) For l = 2, ml = −1, give the magnetic-moment magnitude and z projection in units of µB = eℏ/(2m).
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Question 1 - Solution The sign of an orbital magnetic moment follows the electron charge r L µL (a) Method and calculation T = 2πr/v, |µL| = ev 2πrπr2 = evr 2 , |L| = mvr. µL = −e 2mL = −µB ℏL . (b) Interpretation and further calculation |µL| = µB √ l(l + 1) = √ 6µB . µLz = −mlµB = +µB . Physical check The conventional current circulates opposite to electron motion. The quantum relation uses the same charge sign even though a stationary atomic orbital is not a literal planetary trajectory.

Question 1

The sign of an orbital magnetic moment follows the electron charge

A classical circular electron orbit has radius r and speed v. Use charge −e-e, electron mass m, current magnitude I=e/TI=e/T, and magnetic-moment magnitude Iπr2I\pi r^2.

Diagram shown in the original SVG worksheet.

  1. Derive the vector relation between orbital magnetic moment and angular momentum.

  2. For l=2,ml=−1l=2,m_l=-1, give the magnetic-moment magnitude and z projection in units of μB=eℏ/(2m)\mu_B=e\hbar/(2m).

Question 1 - Solution

The sign of an orbital magnetic moment follows the electron charge

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T=2πr/v,|μL|=ev2πrπr2=evr2,|L|=mvr.T=2\pi r/v,\quad |\mu_L|=\frac{ev}{2\pi r}\pi r^2=\frac{evr}{2},\quad |L|=mvr.𝝁L=−e2m𝑳=−μBℏ𝑳.\boxed{\boldsymbol\mu_L=-\frac{e}{2m}\boldsymbol L=-\frac{\mu_B}{\hbar}\boldsymbol L}.

(b) Interpretation and further calculation

|μL|=μBl(l+1)=6μB.|\mu_L|=\mu_B\sqrt{l(l+1)}=\boxed{\sqrt6\mu_B}.μLz=−mlμB=+μB.\mu_{Lz}=-m_l\mu_B=\boxed{+\mu_B}.

Physical check

The conventional current circulates opposite to electron motion. The quantum relation uses the same charge sign even though a stationary atomic orbital is not a literal planetary trajectory.