Electron Spin — Question 8

Section 40-2 · Physics pages 6606–6607

Question 8 A coherent spin rotation transfers population sinusoidally An electron begins in | + z⟩= (1, 0)T . A supplied rotation about y is Uy(θ) = ( cos(θ/2) −sin(θ/2) sin(θ/2) cos(θ/2) ) . z two rotations Schematic; labels, not drawing lengths, specify the data. (a) Find the output spinor and its negative-z probability. (b) Compare one rotation through π/3 with two successive rotations through π/3.
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Question 8 - Solution A coherent spin rotation transfers population sinusoidally z two rotations (a) Method and calculation Uy(θ) ( 1 0 ) = ( cos(θ/2) sin(θ/2) ) . P−z = sin2(θ/2) . (b) Interpretation and further calculation θ = π/3 : P−z = 1/4 . Uy(π/3)2 = Uy(2π/3) ⇒P−z = 3/4 . Physical check No intermediate measurement is made. Coherent rotation angles add before probabilities are calculated; classical addition of transition probabilities would give the wrong result.

Question 8

A coherent spin rotation transfers population sinusoidally

An electron begins in |+z⟩=(1,0)T|+z\rangle=(1,0)^T. A supplied rotation about y is Uy(θ)=(cos⁡(θ/2)−sin⁡(θ/2)sin⁡(θ/2)cos⁡(θ/2))U_y(\theta)=\begin{pmatrix}\cos(\theta/2)&-\sin(\theta/2)\\\sin(\theta/2)&\cos(\theta/2)\end{pmatrix}.

Diagram shown in the original SVG worksheet.

  1. Find the output spinor and its negative-z probability.

  2. Compare one rotation through π/3\pi/3 with two successive rotations through π/3\pi/3.

Question 8 - Solution

A coherent spin rotation transfers population sinusoidally

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Uy(θ)(10)=(cos⁡(θ/2)sin⁡(θ/2)).U_y(\theta)\binom10=\binom{\cos(\theta/2)}{\sin(\theta/2)}.P−z=sin⁡2(θ/2).\boxed{P_{-z}=\sin^2(\theta/2)}.

(b) Interpretation and further calculation

θ=π/3:P−z=1/4.\theta=\pi/3:\quad\boxed{P_{-z}=1/4}.Uy(π/3)2=Uy(2π/3)⇒P−z=3/4.U_y(\pi/3)^2=U_y(2\pi/3)\Rightarrow\boxed{P_{-z}=3/4}.

Physical check

No intermediate measurement is made. Coherent rotation angles add before probabilities are calculated; classical addition of transition probabilities would give the wrong result.