Electron Spin — Question 1

Section 40-2 · Physics pages 6592–6593

Question 1 Spin magnitude cannot be identified with its largest projection An electron has s = 1/2. Use S2 = s(s + 1)ℏ2 and Sz = msℏ. A measurement prepares ms = +1/2. z x ˆn θ Schematic; labels, not drawing lengths, specify the data. (a) Find the spin magnitude and its z projection. (b) Find ⟨S2 x + S2 y⟩and explain why the spin cannot have all its angular momentum along z.
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Question 1 - Solution Spin magnitude cannot be identified with its largest projection z x ˆn θ (a) Method and calculation |S| = √ s(s + 1)ℏ= √ 3ℏ/2 . Sz = ℏ/2 , Sz/|S| = 1/ √ 3. (b) Interpretation and further calculation ⟨S2 x + S2 y⟩= s(s + 1)ℏ2 −m2 sℏ2. ⟨S2 x + S2 y⟩= ℏ2/2̸ = 0 . Physical check The projection ratio is not evidence for a literal classical spinning axis. Transverse spin components fluctuate in a z eigenstate.

Question 1

Spin magnitude cannot be identified with its largest projection

An electron has s=1/2s=1/2. Use S2=s(s+1)ℏ2S^2=s(s+1)\hbar^2 and Sz=msℏS_z=m_s\hbar. A measurement prepares ms=+1/2m_s=+1/2.

Diagram shown in the original SVG worksheet.

  1. Find the spin magnitude and its z projection.

  2. Find ⟨Sx2+Sy2⟩\langle S_x^2+S_y^2\rangle and explain why the spin cannot have all its angular momentum along z.

Question 1 - Solution

Spin magnitude cannot be identified with its largest projection

Diagram shown in the original SVG worksheet.

(a) Method and calculation

|S|=s(s+1)ℏ=3ℏ/2.|S|=\sqrt{s(s+1)}\hbar=\boxed{\sqrt3\hbar/2}.Sz=ℏ/2,Sz/|S|=1/3.\boxed{S_z=\hbar/2},\qquad S_z/|S|=1/\sqrt3.

(b) Interpretation and further calculation

⟨Sx2+Sy2⟩=s(s+1)ℏ2−ms2ℏ2.\langle S_x^2+S_y^2\rangle=s(s+1)\hbar^2-m_s^2\hbar^2.⟨Sx2+Sy2⟩=ℏ2/2≠0.\boxed{\langle S_x^2+S_y^2\rangle=\hbar^2/2\ne0}.

Physical check

The projection ratio is not evidence for a literal classical spinning axis. Transverse spin components fluctuate in a z eigenstate.