How Lasers Work — Question 3

Section 40-11 · Physics pages 6776–6777

Question 3 A three-level laser must pump more than half its active atoms upward In an ideal three-level laser the pump level relaxes instantly into the upper laser level 2; the laser transition ends in ground level 1. Below lasing threshold use ˙N2 = W(N −N2) −N2/τ and equal laser-level degeneracies. 1 2 pump Schematic; labels, not drawing lengths, specify the data. (a) Find the steady upper population and transparency pump rate. (b) A cavity requires inversion N2 −N1 = .20N. Find the required dimensionless pump Wτ.
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Question 3 - Solution A three-level laser must pump more than half its active atoms upward 1 2 pump (a) Method and calculation 0 = WN −(W + 1/τ)N2 ⇒N2/N = Wτ/(1 + Wτ) . N2 = N1 = N/2 ⇒Wtrτ = 1 . (b) Interpretation and further calculation (N2 −N1)/N = .20 ⇒N2/N = .60. .60 = x/(1 + x), x = Wτ ⇒Wτ = 1.50 . Physical check Transparency balances stimulated emission and absorption but does not overcome cavity loss. The pump level is assumed negligibly populated because its relaxation is very fast.

Question 3

A three-level laser must pump more than half its active atoms upward

In an ideal three-level laser the pump level relaxes instantly into the upper laser level 2; the laser transition ends in ground level 1. Below lasing threshold use Ṅ2=W(N−N2)−N2/τ\dot N_2=W(N-N_2)-N_2/\tau and equal laser-level degeneracies.

Diagram shown in the original SVG worksheet.

  1. Find the steady upper population and transparency pump rate.

  2. A cavity requires inversion N2−N1=.20NN_2-N_1=.20N. Find the required dimensionless pump WτW\tau.

Question 3 - Solution

A three-level laser must pump more than half its active atoms upward

Diagram shown in the original SVG worksheet.

(a) Method and calculation

0=WN−(W+1/τ)N2⇒N2/N=Wτ/(1+Wτ).0=WN-(W+1/\tau)N_2\Rightarrow\boxed{N_2/N=W\tau/(1+W\tau)}.N2=N1=N/2⇒Wtrτ=1.N_2=N_1=N/2\Rightarrow\boxed{W_{\mathrm{tr}}\tau=1}.

(b) Interpretation and further calculation

(N2−N1)/N=.20⇒N2/N=.60.(N_2-N_1)/N=.20\Rightarrow N_2/N=.60..60=x/(1+x),x=Wτ⇒Wτ=1.50..60=x/(1+x),\ x=W\tau\Rightarrow\boxed{W\tau=1.50}.

Physical check

Transparency balances stimulated emission and absorption but does not overcome cavity loss. The pump level is assumed negligibly populated because its relaxation is very fast.