How Lasers Work — Question 1

Section 40-11 · Physics pages 6772–6773

Question 1 Net stimulated gain requires inversion per magnetic sublevel Two levels have populations N1, N2, degeneracies g1, g2, and Einstein coefficients satisfying g1B12 = g2B21. At spectral energy density u, stimulated emission and absorption rates are B21uN2 and B12uN1. N1, g1 N2, g2 ∆E Schematic; labels, not drawing lengths, specify the data. (a) Derive the condition for positive net stimulated emission. (b) For g1 = 2, g2 = 6, and fixed N = N1 + N2, find the upper-population fraction at transparency and decide whether N2 = .70N gives gain.
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Question 1 - Solution Net stimulated gain requires inversion per magnetic sublevel N1, g1 N2, g2 ∆E (a) Method and calculation Rnet = B21u[N2 −(g2/g1)N1]. Rnet > 0 ⇒N2/g2 > N1/g1 . (b) Interpretation and further calculation N2 = 3N1, N = N1 + N2 ⇒N2/N = 3/4 at transparency . N2 = .70N : N2 −3N1 = .70N −.90N = −.20N ⇒net absorption . Physical check A larger total upper-level population is insufficient when that level has more sublevels. The inversion condition compares population per sublevel.

Question 1

Net stimulated gain requires inversion per magnetic sublevel

Two levels have populations N1,N2N_1,N_2, degeneracies g1,g2g_1,g_2, and Einstein coefficients satisfying g1B12=g2B21g_1B_{12}=g_2B_{21}. At spectral energy density u, stimulated emission and absorption rates are B21uN2B_{21}uN_2 and B12uN1B_{12}uN_1.

Diagram shown in the original SVG worksheet.

  1. Derive the condition for positive net stimulated emission.

  2. For g1=2g_1=2, g2=6g_2=6, and fixed N=N1+N2N=N_1+N_2, find the upper-population fraction at transparency and decide whether N2=.70NN_2=.70N gives gain.

Question 1 - Solution

Net stimulated gain requires inversion per magnetic sublevel

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Rnet=B21u[N2−(g2/g1)N1].R_{\mathrm{net}}=B_{21}u[N_2-(g_2/g_1)N_1].Rnet>0⇒N2/g2>N1/g1.R_{\mathrm{net}}>0\Rightarrow\boxed{N_2/g_2>N_1/g_1}.

(b) Interpretation and further calculation

N2=3N1,N=N1+N2⇒N2/N=3/4 at transparency.N_2=3N_1,\ N=N_1+N_2\Rightarrow\boxed{N_2/N=3/4\text{ at transparency}}.N2=.70N:N2−3N1=.70N−.90N=−.20N⇒net absorption.N_2=.70N:\quad N_2-3N_1=.70N-.90N=-.20N\Rightarrow\boxed{\text{net absorption}}.

Physical check

A larger total upper-level population is insufficient when that level has more sublevels. The inversion condition compares population per sublevel.