Some Properties of Atoms — Question 7

Section 40-1 · Physics pages 6584–6585

Question 7 A thermal excited fraction includes the degeneracy ratio A dilute ensemble has levels E0 = 0 and E1 = ∆, with degeneracies g0 = 1 and g1 = 3. It is in thermal equilibrium at a temperature satisfying kBT = ∆/ ln 6. Other levels can be neglected. g0 = 1 g1 = 3 ∆E Schematic; labels, not drawing lengths, specify the data. (a) Find the ratio of excited to ground populations. (b) Find the excited fraction and mean internal energy per atom.
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Question 7 - Solution A thermal excited fraction includes the degeneracy ratio g0 = 1 g1 = 3 ∆E (a) Method and calculation N1 N0 = g1 g0 e−∆/(kBT) = 3e−ln 6. N1/N0 = 1/2 . (b) Interpretation and further calculation f1 = N1/N0 1 + N1/N0 = 1/3 . ⟨E⟩= f1∆= ∆/3 . Physical check Equal populations per individual state are different from equal populations per energy level. Degeneracy contributes to the level population even when the energy is higher.

Question 7

A thermal excited fraction includes the degeneracy ratio

A dilute ensemble has levels E0=0E_0=0 and E1=ΔE_1=\Delta, with degeneracies g0=1g_0=1 and g1=3g_1=3. It is in thermal equilibrium at a temperature satisfying kBT=Δ/ln⁡6k_BT=\Delta/\ln6. Other levels can be neglected.

Diagram shown in the original SVG worksheet.

  1. Find the ratio of excited to ground populations.

  2. Find the excited fraction and mean internal energy per atom.

Question 7 - Solution

A thermal excited fraction includes the degeneracy ratio

Diagram shown in the original SVG worksheet.

(a) Method and calculation

N1N0=g1g0e−Δ/(kBT)=3e−ln⁡6.\frac{N_1}{N_0}=\frac{g_1}{g_0}e^{-\Delta/(k_BT)}=3e^{-\ln6}.N1/N0=1/2.\boxed{N_1/N_0=1/2}.

(b) Interpretation and further calculation

f1=N1/N01+N1/N0=1/3.f_1=\frac{N_1/N_0}{1+N_1/N_0}=\boxed{1/3}.⟨E⟩=f1Δ=Δ/3.\boxed{\langle E\rangle=f_1\Delta=\Delta/3}.

Physical check

Equal populations per individual state are different from equal populations per energy level. Degeneracy contributes to the level population even when the energy is higher.