The Bohr Model of the Hydrogen Atom — Question 10

Section 39-7 · Physics pages 6550–6551

Question 10 Classical radiation would destabilize an orbit without the stationary-state postulate In a hypothetical slowly shrinking circular Coulomb orbit, let E(r) = −K/(2r) with K = kee2. Suppose the radiated power is P(r) = P0(r0/r)4, starting at radius r0. Use dE/dt = −P(r) and treat this classical model formally down to zero radius. radiative shrinkage Schematic; labels, not drawing lengths, specify the data. (a) Derive the radial contraction law. (b) Integrate to obtain the formal collapse time and express it using initial binding B0 = K/(2r0).
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Question 10 - Solution Classical radiation would destabilize an orbit without the stationary-state postulate radiative shrinkage (a) Method and calculation dE dr = K 2r2 ⇒dr dt = −2P0r4 0 Kr2 . r2dr = −2P0r4 0 K dt ⇒r3 −r3 0 3 = −2P0r4 0 K t. (b) Interpretation and further calculation r = 0 : tcollapse = K 6P0r0 . tcollapse = B0/(3P0) . Physical check The classical approximation fails before zero radius, but its loss of stability motivates the need for quantum stationary states. Bohr postulated nonradiating stationary orbits rather than deriving them from classical radiation theory.

Question 10

Classical radiation would destabilize an orbit without the stationary-state postulate

In a hypothetical slowly shrinking circular Coulomb orbit, let E(r)=−𝒦/(2r)E(r)=-\mathcal K/(2r) with 𝒦=kee2\mathcal K=k_ee^2. Suppose the radiated power is P(r)=P0(r0/r)4P(r)=P_0(r_0/r)^4, starting at radius r0r_0. Use dE/dt=−P(r)dE/dt=-P(r) and treat this classical model formally down to zero radius.

Diagram shown in the original SVG worksheet.

  1. Derive the radial contraction law.

  2. Integrate to obtain the formal collapse time and express it using initial binding B0=𝒦/(2r0)B_0=\mathcal K/(2r_0).

Question 10 - Solution

Classical radiation would destabilize an orbit without the stationary-state postulate

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dEdr=𝒦2r2⇒drdt=−2P0r04𝒦r2.\frac{dE}{dr}=\frac{\mathcal K}{2r^2}\Rightarrow\boxed{\frac{dr}{dt}=-\frac{2P_0r_0^4}{\mathcal K r^2}}.r2dr=−2P0r04𝒦dt⇒r3−r033=−2P0r04𝒦t.r^2dr=-\frac{2P_0r_0^4}{\mathcal K}dt\Rightarrow\frac{r^3-r_0^3}{3}=-\frac{2P_0r_0^4}{\mathcal K}t.

(b) Interpretation and further calculation

r=0:tcollapse=𝒦6P0r0.r=0:\quad\boxed{t_{\mathrm{collapse}}=\frac{\mathcal K}{6P_0r_0}}.tcollapse=B0/(3P0).\boxed{t_{\mathrm{collapse}}=B_0/(3P_0)}.

Physical check

The classical approximation fails before zero radius, but its loss of stability motivates the need for quantum stationary states. Bohr postulated nonradiating stationary orbits rather than deriving them from classical radiation theory.