The Bohr Model of the Hydrogen Atom — Question 1

Section 39-7 · Physics pages 6532–6533

Question 1 Coulomb force and angular-momentum quantization jointly determine Bohr energies An electron of mass m moves in a circular orbit around a fixed nucleus of charge +Ze. Use mv2/r = keZe2/r2, mvr = nℏand potential energy U = −keZe2/r, with zero energy at infinite separation. +Ze v r Schematic; labels, not drawing lengths, specify the data. (a) Derive the radius and speed as functions of n and Z. (b) Derive the total energy and its relation to kinetic and potential energies.
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Question 1 - Solution Coulomb force and angular-momentum quantization jointly determine Bohr energies +Ze v r (a) Method and calculation v = nℏ mr, n2ℏ2 mr3 = keZe2 r2 ⇒rn = n2ℏ2 mkeZe2 . vn = keZe2/(nℏ) . (b) Interpretation and further calculation K = keZe2 2r , U = −keZe2 r = −2K ⇒E = −K = U/2. En = −m(keZe2)2 2n2ℏ2 . Physical check The negative total energy indicates binding relative to a separated electron and nucleus. The Bohr orbit is a historical model, not a spatial trajectory assigned by the full wave-function description.

Question 1

Coulomb force and angular-momentum quantization jointly determine Bohr energies

An electron of mass m moves in a circular orbit around a fixed nucleus of charge +Ze+Ze. Use mv2/r=keZe2/r2mv^2/r=k_eZe^2/r^2, mvr=nℏmvr=n\hbar and potential energy U=−keZe2/rU=-k_eZe^2/r, with zero energy at infinite separation.

Diagram shown in the original SVG worksheet.

  1. Derive the radius and speed as functions of n and Z.

  2. Derive the total energy and its relation to kinetic and potential energies.

Question 1 - Solution

Coulomb force and angular-momentum quantization jointly determine Bohr energies

Diagram shown in the original SVG worksheet.

(a) Method and calculation

v=nℏmr,n2ℏ2mr3=keZe2r2⇒rn=n2ℏ2mkeZe2.v=\frac{n\hbar}{mr},\quad\frac{n^2\hbar^2}{mr^3}=\frac{k_eZe^2}{r^2}\Rightarrow\boxed{r_n=\frac{n^2\hbar^2}{mk_eZe^2}}.vn=keZe2/(nℏ).\boxed{v_n=k_eZe^2/(n\hbar)}.

(b) Interpretation and further calculation

K=keZe22r,U=−keZe2r=−2K⇒E=−K=U/2.K=\frac{k_eZe^2}{2r},\quad U=-\frac{k_eZe^2}{r}=-2K\Rightarrow E=-K=U/2.En=−m(keZe2)22n2ℏ2.\boxed{E_n=-\frac{m(k_eZe^2)^2}{2n^2\hbar^2}}.

Physical check

The negative total energy indicates binding relative to a separated electron and nucleus. The Bohr orbit is a historical model, not a spatial trajectory assigned by the full wave-function description.