Energies of a Trapped Electron — Question 7

Section 39-2 · Physics pages 6444–6445

Question 7 A constant potential offset shifts levels without changing transition frequencies A box has energies En = Vb + n2A, where A = π2ℏ2/(2mL2). The interior potential is raised uniformly by a constant ∆V without changing L or the shape of the well. Ignore any external reference detector. n = 1 n = 2 n = 3 E ∆V Schematic; labels, not drawing lengths, specify the data. (a) Find the new energy levels and the shift of a transition n →r. (b) Find the extra time-dependent phase acquired after a duration t and its effect on position density.
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Question 7 - Solution A constant potential offset shifts levels without changing transition frequencies n = 1 n = 2 n = 3 E ∆V (a) Method and calculation En′ = En + ∆V . En′ −Er′ = En −Er = (n2 −r2)A . (b) Interpretation and further calculation Ψ′(x, t) = e−i∆V t/ℏΨ(x, t) . |Ψ′(x, t)|2 = |Ψ(x, t)|2 . Physical check The common offset changes the chosen energy reference. Relative phases between levels and internal transition frequencies remain unchanged.

Question 7

A constant potential offset shifts levels without changing transition frequencies

A box has energies En=Vb+n2AE_n=V_b+n^2A, where A=π2ℏ2/(2mL2)A=\pi^2\hbar^2/(2mL^2). The interior potential is raised uniformly by a constant ΔV\Delta V without changing L or the shape of the well. Ignore any external reference detector.

Diagram shown in the original SVG worksheet.

  1. Find the new energy levels and the shift of a transition n→rn\to r.

  2. Find the extra time-dependent phase acquired after a duration t and its effect on position density.

Question 7 - Solution

A constant potential offset shifts levels without changing transition frequencies

Diagram shown in the original SVG worksheet.

(a) Method and calculation

En′=En+ΔV.\boxed{E_n\prime=E_n+\Delta V}.En′−Er′=En−Er=(n2−r2)A.\boxed{E_n\prime-E_r\prime=E_n-E_r=(n^2-r^2)A}.

(b) Interpretation and further calculation

Ψ′(x,t)=e−iΔVt/ℏΨ(x,t).\boxed{\Psi\prime(x,t)=e^{-i\Delta Vt/\hbar}\Psi(x,t)}.|Ψ′(x,t)|2=|Ψ(x,t)|2.\boxed{|\Psi\prime(x,t)|^2=|\Psi(x,t)|^2}.

Physical check

The common offset changes the chosen energy reference. Relative phases between levels and internal transition frequencies remain unchanged.