String Waves and Matter Waves — Question 10

Section 39-1 · Physics pages 6430–6431

Question 10 Changing the length shifts string and matter-wave frequencies at different rates A fixed mode index n is followed while the confinement length changes slowly from L to L + δL. The string speed v and particle mass m remain constant. Assume ideal adiabatic tracking for the particle. x 0 L Schematic; labels, not drawing lengths, specify the data. (a) Derive the fractional first-order frequency changes for the string and matter wave. (b) Find the exact ratios when the length increases by 10 percent.
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Question 10 - Solution Changing the length shifts string and matter-wave frequencies at different rates x 0 L (a) Method and calculation ωs ∝L−1 ⇒δωs/ωs ≃−δL/L . ωm ∝L−2 ⇒δωm/ωm ≃−2δL/L . (b) Interpretation and further calculation L′ = 1.10L : ωs′/ωs = 1/1.10 = .909091 . ωm′/ωm = 1/(1.10)2 = .826446 . Physical check The mode index stays fixed only under the specified tracking assumption. An abrupt boundary change creates a superposition and is a different problem.

Question 10

Changing the length shifts string and matter-wave frequencies at different rates

A fixed mode index n is followed while the confinement length changes slowly from L to L+δLL+\delta L. The string speed v and particle mass m remain constant. Assume ideal adiabatic tracking for the particle.

Diagram shown in the original SVG worksheet.

  1. Derive the fractional first-order frequency changes for the string and matter wave.

  2. Find the exact ratios when the length increases by 10 percent.

Question 10 - Solution

Changing the length shifts string and matter-wave frequencies at different rates

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ωs∝L−1⇒δωs/ωs≃−δL/L.\omega_s\propto L^{-1}\Rightarrow\boxed{\delta\omega_s/\omega_s\simeq-\delta L/L}.ωm∝L−2⇒δωm/ωm≃−2δL/L.\omega_m\propto L^{-2}\Rightarrow\boxed{\delta\omega_m/\omega_m\simeq-2\delta L/L}.

(b) Interpretation and further calculation

L′=1.10L:ωs′/ωs=1/1.10=.909091.L\prime=1.10L:\quad\boxed{\omega_s\prime/\omega_s=1/1.10=.909091}.ωm′/ωm=1/(1.10)2=.826446.\boxed{\omega_m\prime/\omega_m=1/(1.10)^2=.826446}.

Physical check

The mode index stays fixed only under the specified tracking assumption. An abrupt boundary change creates a superposition and is a different problem.