Barrier Tunneling — Question 10

Section 38-8 · Physics pages 6410–6411

Question 10 Coherent multiple reflections can make two weakly transmitting barriers fully transparent Two identical lossless barriers each have single-barrier transmission probability τ = .100. In a coherent model their total transmitted amplitude is tpair = τeiχ/[1 −(1 −τ)eiϕ], where ϕ is the round-trip phase including reflection phases and χ is an irrelevant overall phase. Exterior velocities are equal. round-trip phase ϕ Schematic; labels, not drawing lengths, specify the data. (a) Derive the transmission probability and evaluate it at resonance ϕ = 2πn. (b) Find the antiresonant transmission at ϕ = (2n + 1)π and compare with the incoherent multiple-reflection result.
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Question 10 - Solution Coherent multiple reflections can make two weakly transmitting barriers fully transparent round-trip phase ϕ (a) Method and calculation T(ϕ) = τ 2 1 + (1 −τ)2 −2(1 −τ) cos ϕ . ϕ = 2πn : Tres = τ 2/[1 −(1 −τ)]2 = 1 . (b) Interpretation and further calculation ϕ = (2n + 1)π : Tanti = τ 2 (2 −τ)2 = .00277008 . Tinc = τ 2 ∞ ∑ j=0 (1 −τ)2j = τ 2 −τ = .0526316 . Physical check The incoherent calculation adds path probabilities, while the coherent model adds amplitudes. Unity transmission requires the appropriate phase and symmetric lossless barriers; it is not predicted by multiplying two isolated transmission probabilities.

Question 10

Coherent multiple reflections can make two weakly transmitting barriers fully transparent

Two identical lossless barriers each have single-barrier transmission probability τ=.100\tau=.100. In a coherent model their total transmitted amplitude is tpair=τeiχ/[1−(1−τ)eiϕ]t_{\mathrm{pair}}=\tau e^{i\chi}/[1-(1-\tau)e^{i\phi}], where ϕ\phi is the round-trip phase including reflection phases and χ\chi is an irrelevant overall phase. Exterior velocities are equal.

Diagram shown in the original SVG worksheet.

  1. Derive the transmission probability and evaluate it at resonance ϕ=2πn\phi=2\pi n.

  2. Find the antiresonant transmission at ϕ=(2n+1)π\phi=(2n+1)\pi and compare with the incoherent multiple-reflection result.

Question 10 - Solution

Coherent multiple reflections can make two weakly transmitting barriers fully transparent

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T(ϕ)=τ21+(1−τ)2−2(1−τ)cos⁡ϕ.\boxed{T(\phi)=\frac{\tau^2}{1+(1-\tau)^2-2(1-\tau)\cos\phi}}.ϕ=2πn:Tres=τ2/[1−(1−τ)]2=1.\phi=2\pi n:\quad\boxed{T_{\mathrm{res}}=\tau^2/[1-(1-\tau)]^2=1}.

(b) Interpretation and further calculation

ϕ=(2n+1)π:Tanti=τ2(2−τ)2=.00277008.\phi=(2n+1)\pi:\quad\boxed{T_{\mathrm{anti}}=\frac{\tau^2}{(2-\tau)^2}=.00277008}.Tinc=τ2∑j=0∞(1−τ)2j=τ2−τ=.0526316.T_{\mathrm{inc}}=\tau^2\sum_{j=0}^{\infty}(1-\tau)^{2j}=\boxed{\frac{\tau}{2-\tau}=.0526316}.

Physical check

The incoherent calculation adds path probabilities, while the coherent model adds amplitudes. Unity transmission requires the appropriate phase and symmetric lossless barriers; it is not predicted by multiplying two isolated transmission probabilities.