Schrödinger's Equation — Question 7

Section 38-6 · Physics pages 6364–6365

Question 7 Probability conservation follows from the wave equation and its complex conjugate A normalizable particle evolves in a real potential V (x, t). Define ρ = Ψ∗Ψ and j = ℏ(Ψ∗∂xΨ −Ψ∂xΨ∗)/(2mi). Use iℏ∂tΨ = −(ℏ2/2m)∂2 xΨ + V Ψ. j(a) j(b) a b Schematic; labels, not drawing lengths, specify the data. (a) Derive the local continuity equation. (b) Express the rate of change of probability in [a, b] in terms of boundary currents and evaluate it for j(a) = .030 s−1 and j(b) = .010 s−1.
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Question 7 - Solution Probability conservation follows from the wave equation and its complex conjugate j(a) j(b) a b (a) Method and calculation ∂tρ = iℏ 2m ( Ψ∗∂2 xΨ −Ψ∂2 xΨ∗) . ∂xj = ℏ 2mi ( Ψ∗∂2 xΨ −Ψ∂2 xΨ∗) ⇒ ∂tρ + ∂xj = 0 . (b) Interpretation and further calculation d dt ∫b a ρ dx = − ∫b a ∂xj dx = j(a) −j(b). ˙P[a,b] = .020 s−1 . Physical check The potential terms cancel because V is real. Positive accumulation means inward flux exceeds outward flux; it does not create probability globally.

Question 7

Probability conservation follows from the wave equation and its complex conjugate

A normalizable particle evolves in a real potential V(x,t)V(x,t). Define ρ=Ψ*Ψ\rho=\Psi^*\Psi and j=ℏ(Ψ*∂xΨ−Ψ∂xΨ*)/(2mi)j=\hbar(\Psi^*\partial_x\Psi-\Psi\partial_x\Psi^*)/(2mi). Use iℏ∂tΨ=−(ℏ2/2m)∂x2Ψ+VΨi\hbar\partial_t\Psi=-(\hbar^2/2m)\partial_x^2\Psi+V\Psi.

Diagram shown in the original SVG worksheet.

  1. Derive the local continuity equation.

  2. Express the rate of change of probability in [a,b][a,b] in terms of boundary currents and evaluate it for j(a)=.030s−1j(a)=.030\,\mathrm{s}^{-1} and j(b)=.010s−1j(b)=.010\,\mathrm{s}^{-1}.

Question 7 - Solution

Probability conservation follows from the wave equation and its complex conjugate

Diagram shown in the original SVG worksheet.

(a) Method and calculation

∂tρ=iℏ2m(Ψ*∂x2Ψ−Ψ∂x2Ψ*).\partial_t\rho=\frac{i\hbar}{2m}\left(\Psi^*\partial_x^2\Psi-\Psi\partial_x^2\Psi^*\right).∂xj=ℏ2mi(Ψ*∂x2Ψ−Ψ∂x2Ψ*)⇒∂tρ+∂xj=0.\partial_xj=\frac{\hbar}{2mi}\left(\Psi^*\partial_x^2\Psi-\Psi\partial_x^2\Psi^*\right)\quad\Rightarrow\quad\boxed{\partial_t\rho+\partial_xj=0}.

(b) Interpretation and further calculation

ddt∫abρdx=−∫ab∂xjdx=j(a)−j(b).\frac{d}{dt}\int_a^b\rho\,dx=-\int_a^b\partial_xj\,dx=j(a)-j(b).Ṗ[a,b]=.020s−1.\boxed{\dot P_{[a,b]}=.020\,\mathrm{s}^{-1}}.

Physical check

The potential terms cancel because V is real. Positive accumulation means inward flux exceeds outward flux; it does not create probability globally.