Electrons and Matter Waves — Question 10

Section 38-5 · Physics pages 6350–6351

Question 10 Energy spread limits path coherence through the spread of matter-wave phase A narrow nonrelativistic electron beam has mean kinetic energy K0 = 100 eV and small rms spread σK = 1.00 eV. For a path difference ∆ℓ, define the linearized rms phase spread σϕ = ∆ℓσk, with k = √2meK/ℏ. Define the coherence scale by σϕ = 1. Use hc = 1240 eV nm and mec2 = 511000 eV. extra path ∆ℓ Schematic; labels, not drawing lengths, specify the data. (a) Derive σk/k0 and calculate the mean wavelength. (b) Find the coherence scale in nanometers and in wavelengths.
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Question 10 - Solution Energy spread limits path coherence through the spread of matter-wave phase extra path ∆ℓ (a) Method and calculation dk dK = k 2K ⇒ σk/k0 ≃σK/(2K0) = .00500 . λ0 = 1240 √ 1022000(100) nm = .122658 nm . (b) Interpretation and further calculation ℓc = 1/σk = 2K0 σK λ0 2π. ℓc/λ0 = 100/π = 31.8310 , ℓc = 3.90433 nm . Physical check This coherence scale uses a specified rms phase criterion and a narrow energy distribution. It is not a universal sharp boundary beyond which all interference disappears.

Question 10

Energy spread limits path coherence through the spread of matter-wave phase

A narrow nonrelativistic electron beam has mean kinetic energy K0=100eVK_0=100\,\mathrm{eV} and small rms spread σK=1.00eV\sigma_K=1.00\,\mathrm{eV}. For a path difference Δℓ\Delta\ell, define the linearized rms phase spread σϕ=Δℓσk\sigma_\phi=\Delta\ell\,\sigma_k, with k=2meK/ℏk=\sqrt{2m_eK}/\hbar. Define the coherence scale by σϕ=1\sigma_\phi=1. Use hc=1240eVnmhc=1240\,\mathrm{eV\,nm} and mec2=511000eVm_ec^2=511000\,\mathrm{eV}.

Diagram shown in the original SVG worksheet.

  1. Derive σk/k0\sigma_k/k_0 and calculate the mean wavelength.

  2. Find the coherence scale in nanometers and in wavelengths.

Question 10 - Solution

Energy spread limits path coherence through the spread of matter-wave phase

Diagram shown in the original SVG worksheet.

(a) Method and calculation

dkdK=k2K⇒σk/k0≃σK/(2K0)=.00500.\frac{dk}{dK}=\frac{k}{2K}\quad\Rightarrow\quad\boxed{\sigma_k/k_0\simeq\sigma_K/(2K_0)=.00500}.λ0=12401022000(100)nm=.122658nm.\boxed{\lambda_0=\frac{1240}{\sqrt{1022000(100)}}\,\mathrm{nm}=.122658\,\mathrm{nm}}.

(b) Interpretation and further calculation

ℓc=1/σk=2K0σKλ02π.\ell_c=1/\sigma_k=\frac{2K_0}{\sigma_K}\frac{\lambda_0}{2\pi}.ℓc/λ0=100/π=31.8310,ℓc=3.90433nm.\boxed{\ell_c/\lambda_0=100/\pi=31.8310},\qquad\boxed{\ell_c=3.90433\,\mathrm{nm}}.

Physical check

This coherence scale uses a specified rms phase criterion and a narrow energy distribution. It is not a universal sharp boundary beyond which all interference disappears.