Light as a Probability Wave — Question 3

Section 38-4 · Physics pages 6316–6317

Question 3 Global phase cancels while a relative phase changes interference Two input amplitudes are initially (a, b) = (1, 1)/ √ 2. Compare transformation G, which multiplies both by eiα, with transformation R, which multiplies only b by eiα. A mixer has outputs (a ± b)/ √ 2. a beiα paths Schematic; labels, not drawing lengths, specify the data. (a) Find output probabilities under G for arbitrary α. (b) Find output probabilities under R at α = π and identify the observable distinction.
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Question 3 - Solution Global phase cancels while a relative phase changes interference a beiα paths (a) Method and calculation c(G) + = eiα, c(G) − = 0. P (G) + = 1, P (G) − = 0 for every α. (b) Interpretation and further calculation c(R) ± = 1 2(1 ± eiα), P (R) ± = 1 2(1 ± cos α). α = π : P (R) + = 0, P (R) − = 1 . Physical check An overall complex phase leaves all absolute squares unchanged. A phase difference between coherent alternatives changes their cross term.

Question 3

Global phase cancels while a relative phase changes interference

Two input amplitudes are initially (a,b)=(1,1)/2(a,b)=(1,1)/\sqrt2. Compare transformation G, which multiplies both by eiαe^{i\alpha}, with transformation R, which multiplies only b by eiαe^{i\alpha}. A mixer has outputs (a±b)/2(a\pm b)/\sqrt2.

Diagram shown in the original SVG worksheet.

  1. Find output probabilities under G for arbitrary α\alpha.

  2. Find output probabilities under R at α=π\alpha=\pi and identify the observable distinction.

Question 3 - Solution

Global phase cancels while a relative phase changes interference

Diagram shown in the original SVG worksheet.

(a) Method and calculation

c+(G)=eiα,c−(G)=0.c_+^{(G)}=e^{i\alpha},\qquad c_-^{(G)}=0.P+(G)=1,P−(G)=0for every α.\boxed{P_+^{(G)}=1,\quad P_-^{(G)}=0}\quad\text{for every }\alpha.

(b) Interpretation and further calculation

c±(R)=12(1±eiα),P±(R)=12(1±cos⁡α).c_\pm^{(R)}=\tfrac12(1\pm e^{i\alpha}),\quad P_\pm^{(R)}=\tfrac12(1\pm\cos\alpha).α=π:P+(R)=0,P−(R)=1.\alpha=\pi:\quad\boxed{P_+^{(R)}=0,\quad P_-^{(R)}=1}.

Physical check

An overall complex phase leaves all absolute squares unchanged. A phase difference between coherent alternatives changes their cross term.