The Relativity of Velocities — Question 5

Section 37-8 · Physics pages 6180–6181

Question 5 A transverse photon remains lightlike after aberration A photon is emitted along +y in a spacecraft frame: ux′ = 0, uy′ = c. The spacecraft moves at v = 0.60c along x. For S′ moving at +v along x, use ux = (ux′ + v)/(1 + vux′/c2) and uy = uy′/[γv(1 + vux′/c2)], with γv = (1 −v2/c2)−1/2. ux uy u Schematic; labels, not drawing lengths, specify the data. (a) Find its laboratory components and speed. (b) Find its laboratory propagation angle from +x.
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Question 5 - Solution A transverse photon remains lightlike after aberration ux uy u (a) Method and calculation ux = 0.60c , uy = c/1.25 = 0.80c . |u| = c √ .602 + .802 = c . (b) Interpretation and further calculation tan θ = uy/ux = 4/3. θ = 53.1301◦. Physical check The boost changes the propagation direction while preserving the magnitude of a vacuum light velocity.

Question 5

A transverse photon remains lightlike after aberration

A photon is emitted along +y in a spacecraft frame: ux′=0u_x\prime=0, uy′=cu_y\prime=c. The spacecraft moves at v=0.60cv=0.60c along x. For S′S\prime moving at +v along x, use ux=(ux′+v)/(1+vux′/c2)u_x=(u_x\prime+v)/(1+vu_x\prime/c^2) and uy=uy′/[γv(1+vux′/c2)]u_y=u_y\prime/[\gamma_v(1+vu_x\prime/c^2)], with γv=(1−v2/c2)−1/2\gamma_v=(1-v^2/c^2)^{-1/2}.

Diagram shown in the original SVG worksheet.

  1. Find its laboratory components and speed.

  2. Find its laboratory propagation angle from +x.

Question 5 - Solution

A transverse photon remains lightlike after aberration

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ux=0.60c,uy=c/1.25=0.80c.\boxed{u_x=0.60c},\qquad\boxed{u_y=c/1.25=0.80c}.|𝒖|=c.602+.802=c.|\mathbf u|=c\sqrt{.60^2+.80^2}=\boxed{c}.

(b) Interpretation and further calculation

tan⁡θ=uy/ux=4/3.\tan\theta=u_y/u_x=4/3.θ=53.1301∘.\boxed{\theta=53.1301^\circ}.

Physical check

The boost changes the propagation direction while preserving the magnitude of a vacuum light velocity.