The Relativity of Length — Question 10

Section 37-5 · Physics pages 6130–6131

Question 10 Contraction increases number density without creating particles A uniform cloud has rest number density n0 and rest volume V0. It moves at v = 0.60c along x. Count particles on simultaneous slices; a boundary fixed in the laboratory has transverse area A. Use γ = (1 −v2/c2)−1/2 and c = 3.00 × 108 m/s. A v Schematic; labels, not drawing lengths, specify the data. (a) Find the laboratory number density. (b) Find the crossing rate through the boundary and verify particle number is unchanged for a comoving cloud volume.
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Question 10 - Solution Contraction increases number density without creating particles A v (a) Method and calculation N = n0V0, V = V0/γ. n = N/V = γn0 = 1.25n0 . (b) Interpretation and further calculation ˙Ncross = nvA = 0.750n0cA . nV = (γn0)(V0/γ) = n0V0 . Physical check Number is invariant for the chosen collection of particles. Density changes because the simultaneous volume used in the count changes.

Question 10

Contraction increases number density without creating particles

A uniform cloud has rest number density n0n_0 and rest volume V0V_0. It moves at v=0.60cv=0.60c along x. Count particles on simultaneous slices; a boundary fixed in the laboratory has transverse area A. Use γ=(1−v2/c2)−1/2\gamma=(1-v^2/c^2)^{-1/2} and c=3.00×108m/sc=3.00\times10^8\,\mathrm{m/s}.

Diagram shown in the original SVG worksheet.

  1. Find the laboratory number density.

  2. Find the crossing rate through the boundary and verify particle number is unchanged for a comoving cloud volume.

Question 10 - Solution

Contraction increases number density without creating particles

Diagram shown in the original SVG worksheet.

(a) Method and calculation

N=n0V0,V=V0/γ.N=n_0V_0,\qquad V=V_0/\gamma.n=N/V=γn0=1.25n0.\boxed{n=N/V=\gamma n_0=1.25n_0}.

(b) Interpretation and further calculation

Ṅcross=nvA=0.750n0cA.\boxed{\dot N_{\mathrm{cross}}=nvA=0.750n_0cA}.nV=(γn0)(V0/γ)=n0V0.nV=(\gamma n_0)(V_0/\gamma)=\boxed{n_0V_0}.

Physical check

Number is invariant for the chosen collection of particles. Density changes because the simultaneous volume used in the count changes.