The Relativity of Simultaneity — Question 8

Section 37-3 · Physics pages 6086–6087

Question 8 Simultaneity in two distinct collinear frames forces coincidence in x Two events are simultaneous in S and also in a frame S′ moving at nonzero v along x. They may differ in y and z. Use ∆t′ = γ(∆t −v∆x/c2), γ = (1 −v2/c2)−1/2; S′ moves at +v along x. Take c = 3.00 × 108 m/s. x y A B v Schematic; labels, not drawing lengths, specify the data. (a) Determine what this implies about ∆x. (b) Decide whether the events must be the same spacetime point, giving an explicit counterexample if not.
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Question 8 - Solution Simultaneity in two distinct collinear frames forces coincidence in x x y A B v (a) Method and calculation ∆t = 0, ∆t′ = 0 ⇒ 0 = −γv∆x/c2. v̸ = 0 ⇒ ∆x = 0 . (b) Interpretation and further calculation A : (t, x, y, z) = (0, 0, 0, 0), B : (0, 0, d, 0), d̸ = 0. ∆t′ = 0, ∆y′ = d̸ = 0 . Physical check A boost along x mixes only x and time. Agreement on simultaneity does not erase transverse separation.

Question 8

Simultaneity in two distinct collinear frames forces coincidence in x

Two events are simultaneous in S and also in a frame S′S\prime moving at nonzero v along x. They may differ in y and z. Use Δt′=γ(Δt−vΔx/c2)\Delta t\prime=\gamma(\Delta t-v\Delta x/c^2), γ=(1−v2/c2)−1/2\gamma=(1-v^2/c^2)^{-1/2}; S′S\prime moves at +v along x. Take c=3.00×108m/sc=3.00\times10^8\,\mathrm{m/s}.

Diagram shown in the original SVG worksheet.

  1. Determine what this implies about Δx\Delta x.

  2. Decide whether the events must be the same spacetime point, giving an explicit counterexample if not.

Question 8 - Solution

Simultaneity in two distinct collinear frames forces coincidence in x

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Δt=0,Δt′=0⇒0=−γvΔx/c2.\Delta t=0,\quad\Delta t\prime=0\quad\Rightarrow\quad0=-\gamma v\Delta x/c^2.v≠0⇒Δx=0.v\ne0\quad\Rightarrow\quad\boxed{\Delta x=0}.

(b) Interpretation and further calculation

A:(t,x,y,z)=(0,0,0,0),B:(0,0,d,0),d≠0.A:(t,x,y,z)=(0,0,0,0),\quad B:(0,0,d,0),\quad d\ne0.Δt′=0,Δy′=d≠0.\boxed{\Delta t\prime=0,\quad\Delta y\prime=d\ne0}.

Physical check

A boost along x mixes only x and time. Agreement on simultaneity does not erase transverse separation.