A New Look at Energy — Question 8

Section 37-11 · Physics pages 6246–6247

Question 8 Two massless particles can form a system with nonzero invariant mass Two photons travel in opposite directions with energies E1 = 3.00 MeV and E2 = 1.00 MeV. Use p = E/c for each and choose +x along photon 1. E1/c E2/c Schematic; labels, not drawing lengths, specify the data. (a) Find the system total energy, momentum and invariant mass. (b) Find the center-of-momentum velocity and the energy of each photon in that frame.
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Question 8 - Solution Two massless particles can form a system with nonzero invariant mass E1/c E2/c (a) Method and calculation E = E1 + E2 = 4.00 MeV, Pc = E1 −E2 = 2.00 MeV. Mc2 = √ E2 −P 2c2 = 2 √ 3 MeV . (b) Interpretation and further calculation V/c = Pc/E = 1/2 , γV = 2/ √ 3. E1′ = γV E1(1 −1/2) = √ 3 MeV = E2′ . Physical check Zero individual rest masses do not imply zero system mass; the system mass depends on the vector sum of momenta.

Question 8

Two massless particles can form a system with nonzero invariant mass

Two photons travel in opposite directions with energies E1=3.00MeVE_1=3.00\,\mathrm{MeV} and E2=1.00MeVE_2=1.00\,\mathrm{MeV}. Use p=E/cp=E/c for each and choose +x along photon 1.

Diagram shown in the original SVG worksheet.

  1. Find the system total energy, momentum and invariant mass.

  2. Find the center-of-momentum velocity and the energy of each photon in that frame.

Question 8 - Solution

Two massless particles can form a system with nonzero invariant mass

Diagram shown in the original SVG worksheet.

(a) Method and calculation

E=E1+E2=4.00MeV,Pc=E1−E2=2.00MeV.E=E_1+E_2=4.00\,\mathrm{MeV},\quad Pc=E_1-E_2=2.00\,\mathrm{MeV}.Mc2=E2−P2c2=23MeV.\boxed{Mc^2=\sqrt{E^2-P^2c^2}=2\sqrt3\,\mathrm{MeV}}.

(b) Interpretation and further calculation

V/c=Pc/E=1/2,γV=2/3.\boxed{V/c=Pc/E=1/2},\quad\gamma_V=2/\sqrt3.E1′=γVE1(1−1/2)=3MeV=E2′.\boxed{E_1\prime=\gamma_VE_1(1-1/2)=\sqrt3\,\mathrm{MeV}=E_2\prime}.

Physical check

Zero individual rest masses do not imply zero system mass; the system mass depends on the vector sum of momenta.