A New Look at Energy — Question 1

Section 37-11 · Physics pages 6232–6233

Question 1 Energy and momentum jointly determine rest mass and kinetic energy A particle has total energy E = 5.00 MeV and momentum such that pc = 4.00 MeV. Use E2 = p2c2 + m2c4, E = γmc2, K = E −mc2, and v = c2p/E. pc E mc2 Schematic; labels, not drawing lengths, specify the data. (a) Find its rest energy and kinetic energy. (b) Find its speed and Lorentz factor, checking the mass-shell identity.
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Question 1 - Solution Energy and momentum jointly determine rest mass and kinetic energy pc E mc2 (a) Method and calculation mc2 = √ E2 −p2c2 = √ 25 −16 MeV = 3.00 MeV . K = 5.00 −3.00 = 2.00 MeV . (b) Interpretation and further calculation v/c = pc/E = 0.800 , γ = E/(mc2) = 5/3 . E2 −(pc)2 = 9.00 MeV2 = (mc2)2 . Physical check Total energy includes rest energy. Subtracting rest energy before using the mass-shell equation would give an inconsistent result.

Question 1

Energy and momentum jointly determine rest mass and kinetic energy

A particle has total energy E=5.00MeVE=5.00\,\mathrm{MeV} and momentum such that pc=4.00MeVpc=4.00\,\mathrm{MeV}. Use E2=p2c2+m2c4E^2=p^2c^2+m^2c^4, E=γmc2E=\gamma mc^2, K=E−mc2K=E-mc^2, and 𝒗=c2𝒑/E\mathbf v=c^2\mathbf p/E.

Diagram shown in the original SVG worksheet.

  1. Find its rest energy and kinetic energy.

  2. Find its speed and Lorentz factor, checking the mass-shell identity.

Question 1 - Solution

Energy and momentum jointly determine rest mass and kinetic energy

Diagram shown in the original SVG worksheet.

(a) Method and calculation

mc2=E2−p2c2=25−16MeV=3.00MeV.mc^2=\sqrt{E^2-p^2c^2}=\sqrt{25-16}\,\mathrm{MeV}=\boxed{3.00\,\mathrm{MeV}}.K=5.00−3.00=2.00MeV.\boxed{K=5.00-3.00=2.00\,\mathrm{MeV}}.

(b) Interpretation and further calculation

v/c=pc/E=0.800,γ=E/(mc2)=5/3.\boxed{v/c=pc/E=0.800},\qquad\boxed{\gamma=E/(mc^2)=5/3}.E2−(pc)2=9.00MeV2=(mc2)2.\boxed{E^2-(pc)^2=9.00\,\mathrm{MeV}^2=(mc^2)^2}.

Physical check

Total energy includes rest energy. Subtracting rest energy before using the mass-shell equation would give an inconsistent result.