The Postulates — Question 10

Section 37-1 · Physics pages 6050–6051

Question 10 Changing source velocity does not change a vacuum flight time Two sources cross the same laboratory point at t = 0 with different velocities and each emits a pulse toward a fixed detector at x = D. The pulses travel through vacuum. A competing emission model proposes laboratory speeds c + v1 and c + v2. x O D two pulses Schematic; labels, not drawing lengths, specify the data. (a) Predict the detection-time difference using the light postulate. (b) For v1 = 0.20c, v2 = −0.20c, find the difference predicted by the competing model, expressed in units of D/c.
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Question 10 - Solution Changing source velocity does not change a vacuum flight time x O D two pulses (a) Method and calculation x1 = ct, x2 = ct ⇒ t1 = t2 = D/c. ∆t = t2 −t1 = 0 . (b) Interpretation and further calculation tmodel 1 = 5D 6c , tmodel 2 = 5D 4c . ∆tmodel = 5D 12c . Physical check The emissions are colocated and simultaneous in the laboratory, so no remote synchronization ambiguity enters the comparison at one detector.

Question 10

Changing source velocity does not change a vacuum flight time

Two sources cross the same laboratory point at t=0t=0 with different velocities and each emits a pulse toward a fixed detector at x=Dx=D. The pulses travel through vacuum. A competing emission model proposes laboratory speeds c+v1c+v_1 and c+v2c+v_2.

Diagram shown in the original SVG worksheet.

  1. Predict the detection-time difference using the light postulate.

  2. For v1=0.20cv_1=0.20c, v2=−0.20cv_2=-0.20c, find the difference predicted by the competing model, expressed in units of D/cD/c.

Question 10 - Solution

Changing source velocity does not change a vacuum flight time

Diagram shown in the original SVG worksheet.

(a) Method and calculation

x1=ct,x2=ct⇒t1=t2=D/c.x_1=ct,\quad x_2=ct\quad\Rightarrow\quad t_1=t_2=D/c.Δt=t2−t1=0.\boxed{\Delta t=t_2-t_1=0}.

(b) Interpretation and further calculation

t1model=5D6c,t2model=5D4c.t_1^{\mathrm{model}}=\frac{5D}{6c},\qquad t_2^{\mathrm{model}}=\frac{5D}{4c}.Δtmodel=5D12c.\boxed{\Delta t_{\mathrm{model}}=\frac{5D}{12c}}.

Physical check

The emissions are colocated and simultaneous in the laboratory, so no remote synchronization ambiguity enters the comparison at one detector.