The Postulates — Question 8

Section 37-1 · Physics pages 6046–6047

Question 8 Round-trip light timing alone cannot isolate directional speeds A source and mirror are fixed a distance L apart. Consider a hypothetical timing convention with outward speed c+ = c/(1 + ϵ) and return speed c−= c/(1 −ϵ), where |ϵ| < 1. x A B c+ c− Schematic; labels, not drawing lengths, specify the data. (a) Find the two one-way times and the round-trip average speed. (b) Explain what extra convention makes both assigned one-way speeds equal to c.
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Question 8 - Solution Round-trip light timing alone cannot isolate directional speeds x A B c+ c− (a) Method and calculation t+ = L(1 + ϵ)/c, t−= L(1 −ϵ)/c. tround = 2L/c, 2L/tround = c . (b) Interpretation and further calculation t+ = t− ⇐⇒ ϵ = 0 . tB = (temit + treceive)/2 ⇒ c+ = c−= c. Physical check Einstein synchronization assigns equal outbound and inbound times. A round-trip result alone does not determine that distant-clock convention.

Question 8

Round-trip light timing alone cannot isolate directional speeds

A source and mirror are fixed a distance L apart. Consider a hypothetical timing convention with outward speed c+=c/(1+ϵ)c_+=c/(1+\epsilon) and return speed c−=c/(1−ϵ)c_-=c/(1-\epsilon), where |ϵ|<1|\epsilon|<1.

Diagram shown in the original SVG worksheet.

  1. Find the two one-way times and the round-trip average speed.

  2. Explain what extra convention makes both assigned one-way speeds equal to c.

Question 8 - Solution

Round-trip light timing alone cannot isolate directional speeds

Diagram shown in the original SVG worksheet.

(a) Method and calculation

t+=L(1+ϵ)/c,t−=L(1−ϵ)/c.t_+=L(1+\epsilon)/c,\qquad t_-=L(1-\epsilon)/c.tround=2L/c,2L/tround=c.t_{\mathrm{round}}=2L/c,\qquad\boxed{2L/t_{\mathrm{round}}=c}.

(b) Interpretation and further calculation

t+=t−⇔ϵ=0.t_+=t_-\quad\Longleftrightarrow\quad\boxed{\epsilon=0}.tB=(temit+treceive)/2⇒c+=c−=c.t_B=(t_{\mathrm{emit}}+t_{\mathrm{receive}})/2\quad\Rightarrow\quad c_+=c_-=c.

Physical check

Einstein synchronization assigns equal outbound and inbound times. A round-trip result alone does not determine that distant-clock convention.