The Postulates — Question 4

Section 37-1 · Physics pages 6038–6039

Question 4 Two opposite null rays constrain the mixing of space and time Assume a linear one-dimensional map x′ = A(x −vt) and t′ = B(t −κx), with positive A and B. Require both x = ct and x = −ct to map to vacuum rays of speeds +c and −c. x ct x = ±ct Spacetime sketch; the vertical coordinate is ct. Labels specify events and worldlines. (a) Write the two constraints imposed by the rays. (b) Solve for B/A and κ, without determining the common scale A.
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Question 4 - Solution Two opposite null rays constrain the mixing of space and time x ct x = ±ct (a) Method and calculation A(c −v) = cB(1 −κc). A(c + v) = cB(1 + κc). (b) Interpretation and further calculation 2Ac = 2cB ⇒ B = A . 2Av = 2c2Bκ ⇒ κ = v/c2 . Physical check Light-speed invariance fixes the time-space mixing here. Reciprocity and the inverse map are still needed to fix A.

Question 4

Two opposite null rays constrain the mixing of space and time

Assume a linear one-dimensional map x′=A(x−vt)x\prime=A(x-vt) and t′=B(t−κx)t\prime=B(t-\kappa x), with positive A and B. Require both x=ctx=ct and x=−ctx=-ct to map to vacuum rays of speeds +c+c and −c-c.

Diagram shown in the original SVG worksheet.

  1. Write the two constraints imposed by the rays.

  2. Solve for B/A and κ\kappa, without determining the common scale A.

Question 4 - Solution

Two opposite null rays constrain the mixing of space and time

Diagram shown in the original SVG worksheet.

(a) Method and calculation

A(c−v)=cB(1−κc).A(c-v)=cB(1-\kappa c).A(c+v)=cB(1+κc).A(c+v)=cB(1+\kappa c).

(b) Interpretation and further calculation

2Ac=2cB⇒B=A.2Ac=2cB\quad\Rightarrow\quad\boxed{B=A}.2Av=2c2Bκ⇒κ=v/c2.2Av=2c^2B\kappa\quad\Rightarrow\quad\boxed{\kappa=v/c^2}.

Physical check

Light-speed invariance fixes the time-space mixing here. Reciprocity and the inverse map are still needed to fix A.