Diffraction by Organized Layers — Question 4

Section 36-9 · Physics pages 6018–6019

Question 4 Squared-sine peak ratios identify the first allowed face-centered families For a monatomic face-centered cubic crystal, allowed reflections have h,k,l all odd or all even. First-order Bragg peaks obey sin2 θ = λ2(h2 + k2 + l2)/(4a2). The first three peaks have sin2 θ = 0.120, 0.160, 0.320 at λ = 0.154 nm. sin2 θ I Schematic; labels, not drawing lengths, specify the data. (a) Identify the first three plane families, using the stated selection rule. (b) Calculate a independently from the first and second peaks and check agreement.
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Question 4 - Solution Squared-sine peak ratios identify the first allowed face-centered families sin2 θ I (a) Method and calculation 0.120 : 0.160 : 0.320 = 3 : 4 : 8. (111) : 3, (200) : 4, (220) : 8 . (b) Interpretation and further calculation a111 = λ √ 3 2 √ 0.120 = 0.385 nm . a200 = λ √ 4 2 √ 0.160 = 0.385 nm . Physical check Peak ratios should be combined with reflection conditions; unrestricted sums of squares would predict additional peaks that are absent in this lattice.

Question 4

Squared-sine peak ratios identify the first allowed face-centered families

For a monatomic face-centered cubic crystal, allowed reflections have h,k,l all odd or all even. First-order Bragg peaks obey sin⁡2θ=λ2(h2+k2+l2)/(4a2)\sin^2\theta=\lambda^2(h^2+k^2+l^2)/(4a^2). The first three peaks have sin⁡2θ=0.120,0.160,0.320\sin^2\theta=0.120,0.160,0.320 at λ=0.154nm\lambda=0.154\,\mathrm{nm}.

Diagram shown in the original SVG worksheet.

  1. Identify the first three plane families, using the stated selection rule.

  2. Calculate a independently from the first and second peaks and check agreement.

Question 4 - Solution

Squared-sine peak ratios identify the first allowed face-centered families

Diagram shown in the original SVG worksheet.

(a) Method and calculation

0.120:0.160:0.320=3:4:8.0.120:0.160:0.320=3:4:8.(111):3,(200):4,(220):8.\boxed{(111):3,\quad(200):4,\quad(220):8}.

(b) Interpretation and further calculation

a111=λ320.120=0.385nm.\boxed{a_{111}=\frac{\lambda\sqrt3}{2\sqrt{0.120}}=0.385\,\mathrm{nm}}.a200=λ420.160=0.385nm.\boxed{a_{200}=\frac{\lambda\sqrt4}{2\sqrt{0.160}}=0.385\,\mathrm{nm}}.

Physical check

Peak ratios should be combined with reflection conditions; unrestricted sums of squares would predict additional peaks that are absent in this lattice.