Diffraction by a Single Slit: Locating the Minima — Question 6

Section 36-2 · Physics pages 5882–5883

Question 6 A rectangular opening diffracts more strongly along its narrower dimension A uniformly illuminated rectangular aperture has horizontal width ax and vertical height ay. In a paraxial focal plane, its first dark lines are x = ±fλ/ax and y = ±fλ/ay. Let f = 0.50 m, λ = 600 nm, and central-lobe dimensions Wx = 6.0 mm, Wy = 2.0 mm. ax ay central lobe Schematic; labels, not drawing lengths, specify the data. (a) Infer both aperture dimensions. (b) Predict the central-lobe dimensions if the aperture is rotated by 90◦about the optical axis.
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Question 6 - Solution A rectangular opening diffracts more strongly along its narrower dimension ax ay central lobe (a) Method and calculation Wx = 2fλ/ax, Wy = 2fλ/ay. ax = 0.100 mm, ay = 0.300 mm . (b) Interpretation and further calculation a′ x = ay, a′ y = ax. W ′ x = 2.0 mm, W ′ y = 6.0 mm . Physical check The elongated diffraction pattern is perpendicular to the long dimension of the opening.

Question 6

A rectangular opening diffracts more strongly along its narrower dimension

A uniformly illuminated rectangular aperture has horizontal width axa_x and vertical height aya_y. In a paraxial focal plane, its first dark lines are x=±fλ/axx=\pm f\lambda/a_x and y=±fλ/ayy=\pm f\lambda/a_y. Let f=0.50mf=0.50\,\mathrm m, λ=600nm\lambda=600\,\mathrm{nm}, and central-lobe dimensions Wx=6.0mmW_x=6.0\,\mathrm{mm}, Wy=2.0mmW_y=2.0\,\mathrm{mm}.

Diagram shown in the original SVG worksheet.

  1. Infer both aperture dimensions.

  2. Predict the central-lobe dimensions if the aperture is rotated by 90∘90^\circ about the optical axis.

Question 6 - Solution

A rectangular opening diffracts more strongly along its narrower dimension

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Wx=2fλ/ax,Wy=2fλ/ay.W_x=2f\lambda/a_x,\quad W_y=2f\lambda/a_y.ax=0.100mm,ay=0.300mm.\boxed{a_x=0.100\,\mathrm{mm},\quad a_y=0.300\,\mathrm{mm}}.

(b) Interpretation and further calculation

ax′=ay,ay′=ax.a_x^\prime=a_y,\quad a_y^\prime=a_x.Wx′=2.0mm,Wy′=6.0mm.\boxed{W_x^\prime=2.0\,\mathrm{mm},\quad W_y^\prime=6.0\,\mathrm{mm}}.

Physical check

The elongated diffraction pattern is perpendicular to the long dimension of the opening.