Diffraction and the Wave Theory of Light — Question 2

Section 36-1 · Physics pages 5854–5855

Question 2 Successive Fresnel half-period zones have nearly equal areas A plane wave illuminates a circular aperture, and an axial point is distance L = 1.00 m away. Define zone boundary rm by √ L2 + r2m −L = mλ/2, with λ = 600 nm. Use the paraxial regime rm ≪L. r4 aperture-plane Fresnel zones Schematic; labels, not drawing lengths, specify the data. (a) Derive the approximate radius and area of the mth annular zone. (b) Find the first and fourth boundary radii and estimate the relative correction to r2 4 from the exact geometry.
Show solutionHide solution
Question 2 - Solution Successive Fresnel half-period zones have nearly equal areas r4 aperture-plane Fresnel zones (a) Method and calculation r2 m 2L ≃mλ 2 =⇒r2 m ≃mλL . Am = π(r2 m −r2 m−1) ≃πλL . (b) Interpretation and further calculation r1 = 0.774597 mm, r4 = 1.54919 mm . r2 m = mλL + m2λ2/4 =⇒ϵ4 = 4λ/(4L) = 6.0 × 10−7 . Physical check Equal annular areas help explain comparable contributions from successive zones, while their phases alternate by approximately pi.

Question 2

Successive Fresnel half-period zones have nearly equal areas

A plane wave illuminates a circular aperture, and an axial point is distance L=1.00mL=1.00\,\mathrm m away. Define zone boundary rmr_m by L2+rm2−L=mλ/2\sqrt{L^2+r_m^2}-L=m\lambda/2, with λ=600nm\lambda=600\,\mathrm{nm}. Use the paraxial regime rm≪Lr_m\ll L.

Diagram shown in the original SVG worksheet.

  1. Derive the approximate radius and area of the mth annular zone.

  2. Find the first and fourth boundary radii and estimate the relative correction to r42r_4^2 from the exact geometry.

Question 2 - Solution

Successive Fresnel half-period zones have nearly equal areas

Diagram shown in the original SVG worksheet.

(a) Method and calculation

rm22L≃mλ2⇒rm2≃mλL.\frac{r_m^2}{2L}\simeq\frac{m\lambda}{2}\Longrightarrow\boxed{r_m^2\simeq m\lambda L}.𝒜m=π(rm2−rm−12)≃πλL.\boxed{\mathcal A_m=\pi(r_m^2-r_{m-1}^2)\simeq\pi\lambda L}.

(b) Interpretation and further calculation

r1=0.774597mm,r4=1.54919mm.\boxed{r_1=0.774597\,\mathrm{mm},\quad r_4=1.54919\,\mathrm{mm}}.rm2=mλL+m2λ2/4⇒ϵ4=4λ/(4L)=6.0×10−7.r_m^2=m\lambda L+m^2\lambda^2/4\Longrightarrow\boxed{\epsilon_4=4\lambda/(4L)=6.0\times10^{-7}}.

Physical check

Equal annular areas help explain comparable contributions from successive zones, while their phases alternate by approximately pi.