Interference from Thin Films — Question 5

Section 35-6 · Physics pages 5820–5821

Question 5 Adjacent spectral maxima determine thickness without guessing an order A nondispersive film of index 1.40 in air is observed in normal reflection. Adjacent reflected maxima occur at vacuum wavelengths 700 nm and 500 nm, with no maximum between them. There is one relative reflection phase reversal. n0 nf ns t adjacent maxima: 700, 500 nm Schematic; labels, not drawing lengths, specify the data. (a) Use the adjacent-order condition to determine D = 2nt and the film thickness. (b) Identify the integer order m in D = (m + 1/2)λ0 for each wavelength and verify adjacency.
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Question 5 - Solution Adjacent spectral maxima determine thickness without guessing an order n0 nf ns t adjacent maxima: 700, 500 nm (a) Method and calculation D/λ500 −D/λ700 = 1 =⇒D = λ500λ700 λ700 −λ500 . D = 1750 nm, t = D/(2n) = 625 nm . (b) Interpretation and further calculation 1750/700 = 2.5 =⇒m700 = 2 . 1750/500 = 3.5 =⇒m500 = 3, m500 −m700 = 1 . Physical check It is the reciprocal wavelength that advances uniformly with interference order when the index is nondispersive.

Question 5

Adjacent spectral maxima determine thickness without guessing an order

A nondispersive film of index 1.40 in air is observed in normal reflection. Adjacent reflected maxima occur at vacuum wavelengths 700nm700\,\mathrm{nm} and 500nm500\,\mathrm{nm}, with no maximum between them. There is one relative reflection phase reversal.

Diagram shown in the original SVG worksheet.

  1. Use the adjacent-order condition to determine D=2ntD=2nt and the film thickness.

  2. Identify the integer order m in D=(m+1/2)λ0D=(m+1/2)\lambda_0 for each wavelength and verify adjacency.

Question 5 - Solution

Adjacent spectral maxima determine thickness without guessing an order

Diagram shown in the original SVG worksheet.

(a) Method and calculation

D/λ500−D/λ700=1⇒D=λ500λ700λ700−λ500.D/\lambda_{500}-D/\lambda_{700}=1\Longrightarrow D=\frac{\lambda_{500}\lambda_{700}}{\lambda_{700}-\lambda_{500}}.D=1750nm,t=D/(2n)=625nm.\boxed{D=1750\,\mathrm{nm},\quad t=D/(2n)=625\,\mathrm{nm}}.

(b) Interpretation and further calculation

1750/700=2.5⇒m700=2.1750/700=2.5\Longrightarrow\boxed{m_{700}=2}.1750/500=3.5⇒m500=3,m500−m700=1.1750/500=3.5\Longrightarrow\boxed{m_{500}=3,\quad m_{500}-m_{700}=1}.

Physical check

It is the reciprocal wavelength that advances uniformly with interference order when the index is nondispersive.