Light as a Wave — Question 9

Section 35-1 · Physics pages 5728–5729

Question 9 A moving boundary between two media tunes optical phase A straight path of fixed length L contains lengths x and L-x of indices n1 = 1.60 and n2 = 1.30. A movable boundary increases x at rate u = 2.0 µm/s. Use monochromatic vacuum wavelength 600 nm and quasistatic propagation; neglect Doppler corrections to the material indices. n1 n2 u x Schematic; labels, not drawing lengths, specify the data. (a) Find the optical phase rate relative to an unchanged reference path. (b) Find the time for one phase cycle and the boundary travel in that time.
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Question 9 - Solution A moving boundary between two media tunes optical phase n1 n2 u x (a) Method and calculation L = n1x + n2(L −x), ˙L = (n1 −n2)u = 0.60 µm/s. ˙ϕ = 2π λ0 ˙L = 2π rad/s . (b) Interpretation and further calculation T = 2π/ ˙ϕ = 1.00 s . ∆x = uT = 2.00 µm = λ0/(n1 −n2) . Physical check Translating a boundary between identical indices would produce no phase tuning, regardless of the geometric motion.

Question 9

A moving boundary between two media tunes optical phase

A straight path of fixed length L contains lengths x and L-x of indices n1=1.60n_1=1.60 and n2=1.30n_2=1.30. A movable boundary increases x at rate u=2.0μm/su=2.0\,\mu\mathrm{m/s}. Use monochromatic vacuum wavelength 600nm600\,\mathrm{nm} and quasistatic propagation; neglect Doppler corrections to the material indices.

Diagram shown in the original SVG worksheet.

  1. Find the optical phase rate relative to an unchanged reference path.

  2. Find the time for one phase cycle and the boundary travel in that time.

Question 9 - Solution

A moving boundary between two media tunes optical phase

Diagram shown in the original SVG worksheet.

(a) Method and calculation

ℒ=n1x+n2(L−x),ℒ̇=(n1−n2)u=0.60μm/s.\mathcal L=n_1x+n_2(L-x),\quad\dot{\mathcal L}=(n_1-n_2)u=0.60\,\mu\mathrm{m/s}.ϕ̇=2πλ0ℒ̇=2πrad/s.\boxed{\dot\phi=\frac{2\pi}{\lambda_0}\dot{\mathcal L}=2\pi\,\mathrm{rad/s}}.

(b) Interpretation and further calculation

T=2π/ϕ̇=1.00s.\boxed{T=2\pi/\dot\phi=1.00\,\mathrm s}.Δx=uT=2.00μm=λ0/(n1−n2).\boxed{\Delta x=uT=2.00\,\mu\mathrm m=\lambda_0/(n_1-n_2)}.

Physical check

Translating a boundary between identical indices would produce no phase tuning, regardless of the geometric motion.