Three Proofs — Question 5

Section 34-8 · Physics pages 5700–5701

Question 5 Adding two surface equations proves the thin-lens formula A thin lens of index nl is surrounded by the same index n0 on both sides. Surface radii R1 and R2 are positive for centers to the right. Let q1 be the first surface image distance. In the zero-thickness limit, the second surface object distance is p2=-q1. n0 nl n0 Schematic; labels, not drawing lengths, specify the data. (a) Write the two spherical-surface equations and add them, showing cancellation of the intermediate image. (b) Derive both the thin-lens relation and lensmaker power.
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Question 5 - Solution Adding two surface equations proves the thin-lens formula n0 nl n0 (a) Method and calculation n0 p + nl q1 = nl −n0 R1 , nl −q1 + n0 q = n0 −nl R2 . n0(1/p + 1/q) = (nl −n0)(1/R1 −1/R2). (b) Interpretation and further calculation 1/p + 1/q = 1/f . 1/f = (nl/n0 −1)(1/R1 −1/R2) . Physical check Cancellation requires negligible thickness and identical exterior indices; silently keeping a finite separation would invalidate this particular proof.

Question 5

Adding two surface equations proves the thin-lens formula

A thin lens of index nl is surrounded by the same index n0 on both sides. Surface radii R1 and R2 are positive for centers to the right. Let q1 be the first surface image distance. In the zero-thickness limit, the second surface object distance is p2=-q1.

Diagram shown in the original SVG worksheet.

  1. Write the two spherical-surface equations and add them, showing cancellation of the intermediate image.

  2. Derive both the thin-lens relation and lensmaker power.

Question 5 - Solution

Adding two surface equations proves the thin-lens formula

Diagram shown in the original SVG worksheet.

(a) Method and calculation

n0p+nlq1=nl−n0R1,nl−q1+n0q=n0−nlR2.\frac{n_0}{p}+\frac{n_l}{q_1}=\frac{n_l-n_0}{R_1},\quad\frac{n_l}{-q_1}+\frac{n_0}{q}=\frac{n_0-n_l}{R_2}.n0(1/p+1/q)=(nl−n0)(1/R1−1/R2).n_0(1/p+1/q)=(n_l-n_0)(1/R_1-1/R_2).

(b) Interpretation and further calculation

1/p+1/q=1/f.\boxed{1/p+1/q=1/f}.1/f=(nl/n0−1)(1/R1−1/R2).\boxed{1/f=(n_l/n_0-1)(1/R_1-1/R_2)}.

Physical check

Cancellation requires negligible thickness and identical exterior indices; silently keeping a finite separation would invalidate this particular proof.