Three Proofs — Question 1

Section 34-8 · Physics pages 5692–5693

Question 1 The paraxial mirror equation follows by adding the two ray angles A real axial object and its real image are distances p and q in front of a concave spherical mirror of radius R. A ray reflects at small height h. Neglect surface sag to first order. Define small positive angles alpha=h/p, beta=h/q, and normal tilt gamma=h/R. F C V Schematic; labels, not drawing lengths, specify the data. (a) Use the reflection relation alpha+beta=2 gamma to derive the mirror equation. (b) Take the distant-object limit and identify where the paraxial approximation entered the argument.
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Question 1 - Solution The paraxial mirror equation follows by adding the two ray angles F C V (a) Method and calculation α + β = 2γ ⇒h/p + h/q = 2h/R. h̸ = 0 : 1/p + 1/q = 2/R . (b) Interpretation and further calculation p →∞: q = f = R/2, 1/p + 1/q = 1/f . tan α ≃α, tan β ≃β, sin γ ≃γ (|h/p|, |h/q|, |h/R| ≪1). Physical check The axial ray alone gives no focusing condition; requiring neighboring nonzero-height rays to share a focus supplies the equation.

Question 1

The paraxial mirror equation follows by adding the two ray angles

A real axial object and its real image are distances p and q in front of a concave spherical mirror of radius R. A ray reflects at small height h. Neglect surface sag to first order. Define small positive angles alpha=h/p, beta=h/q, and normal tilt gamma=h/R.

Diagram shown in the original SVG worksheet.

  1. Use the reflection relation alpha+beta=2 gamma to derive the mirror equation.

  2. Take the distant-object limit and identify where the paraxial approximation entered the argument.

Question 1 - Solution

The paraxial mirror equation follows by adding the two ray angles

Diagram shown in the original SVG worksheet.

(a) Method and calculation

α+β=2γ⇒h/p+h/q=2h/R.\alpha+\beta=2\gamma\Rightarrow h/p+h/q=2h/R.h≠0:1/p+1/q=2/R.h\ne0:\quad\boxed{1/p+1/q=2/R}.

(b) Interpretation and further calculation

p→∞:q=f=R/2,1/p+1/q=1/f.p\to\infty:\quad\boxed{q=f=R/2,\quad1/p+1/q=1/f}.tan⁡α≃α,tan⁡β≃β,sin⁡γ≃γ(|h/p|,|h/q|,|h/R|≪1).\tan\alpha\simeq\alpha,\quad\tan\beta\simeq\beta,\quad\sin\gamma\simeq\gamma\quad(|h/p|,|h/q|,|h/R|\ll1).

Physical check

The axial ray alone gives no focusing condition; requiring neighboring nonzero-height rays to share a focus supplies the equation.