Optical Instruments — Question 10

Section 34-7 · Physics pages 5690–5691

Question 10 An eye pupil smaller than the exit pupil discards objective area An ideal afocal telescope has objective diameter 60 mm and angular magnification magnitude 10. The centered eye pupil diameter is 3 mm. Assume uniform pupil illumination and no other loss or vignetting. exit pupil smaller eye pupil Schematic; labels, not drawing lengths, specify the data. (a) Find the exit-pupil diameter and the fraction of its light admitted by the eye. (b) Find the effective diameter of the objective region whose rays can reach the eye.
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Question 10 - Solution An eye pupil smaller than the exit pupil discards objective area exit pupil smaller eye pupil (a) Method and calculation Dexit = Do/|M| = 60/10 = 6 mm . Peye/Pexit = (Deye/Dexit)2 = (3/6)2 = 1/4 . (b) Interpretation and further calculation Do,effective = |M|Deye. Do,effective = 30 mm . Physical check Increasing objective diameter beyond the pupil-matched value does not deliver all of the extra collected light through this fixed centered eye pupil.

Question 10

An eye pupil smaller than the exit pupil discards objective area

An ideal afocal telescope has objective diameter 60 mm and angular magnification magnitude 10. The centered eye pupil diameter is 3 mm. Assume uniform pupil illumination and no other loss or vignetting.

Diagram shown in the original SVG worksheet.

  1. Find the exit-pupil diameter and the fraction of its light admitted by the eye.

  2. Find the effective diameter of the objective region whose rays can reach the eye.

Question 10 - Solution

An eye pupil smaller than the exit pupil discards objective area

Diagram shown in the original SVG worksheet.

(a) Method and calculation

Dexit=Do/|M|=60/10=6mm.\boxed{D_{\mathrm{exit}}=D_o/|M|=60/10=6\,\mathrm{mm}}.Peye/Pexit=(Deye/Dexit)2=(3/6)2=1/4.\boxed{P_{\mathrm{eye}}/P_{\mathrm{exit}}=(D_{\mathrm{eye}}/D_{\mathrm{exit}})^2=(3/6)^2=1/4}.

(b) Interpretation and further calculation

Do,effective=|M|Deye.D_{o,\mathrm{effective}}=|M|D_{\mathrm{eye}}.Do,effective=30mm.\boxed{D_{o,\mathrm{effective}}=30\,\mathrm{mm}}.

Physical check

Increasing objective diameter beyond the pupil-matched value does not deliver all of the extra collected light through this fixed centered eye pupil.