Thin Lenses — Question 4

Section 34-6 · Physics pages 5658–5659

Question 4 A surrounding liquid can weaken or reverse a glass lens A thin lens of glass index ng=1.50 has focal length 20 cm in air. In a uniform surrounding medium of index nm, use 1/f = (ng/nm −1)G, where G = 1/R1 −1/R2 is fixed by its shape. F F ′ medium nm Schematic; labels, not drawing lengths, specify the data. (a) Find G and the focal length in index nm=1.25. (b) Find the focal length in index nm=1.60 and classify the lens behavior.
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Question 4 - Solution A surrounding liquid can weaken or reverse a glass lens F F ′ medium nm (a) Method and calculation 1/(20 cm) = (1.50 −1)G ⇒G = 0.10 cm−1 . 1/f = (1.50/1.25 −1)(0.10) = 0.020 ⇒f = 50 cm . (b) Interpretation and further calculation 1/f = (1.50/1.60 −1)(0.10) = −0.00625 cm−1. f = −160 cm diverging in the higher-index surrounding medium. Physical check Lens shape alone does not determine convergence; the refractive-index contrast controls the sign of the power.

Question 4

A surrounding liquid can weaken or reverse a glass lens

A thin lens of glass index ng=1.50 has focal length 20 cm in air. In a uniform surrounding medium of index nm, use 1/f=(ng/nm−1)G1/f=(n_g/n_m-1)G, where G=1/R1−1/R2G=1/R_1-1/R_2 is fixed by its shape.

Diagram shown in the original SVG worksheet.

  1. Find G and the focal length in index nm=1.25.

  2. Find the focal length in index nm=1.60 and classify the lens behavior.

Question 4 - Solution

A surrounding liquid can weaken or reverse a glass lens

Diagram shown in the original SVG worksheet.

(a) Method and calculation

1/(20cm)=(1.50−1)G⇒G=0.10cm−1.1/(20\,\mathrm{cm})=(1.50-1)G\Rightarrow\boxed{G=0.10\,\mathrm{cm^{-1}}}.1/f=(1.50/1.25−1)(0.10)=0.020⇒f=50cm.1/f=(1.50/1.25-1)(0.10)=0.020\Rightarrow\boxed{f=50\,\mathrm{cm}}.

(b) Interpretation and further calculation

1/f=(1.50/1.60−1)(0.10)=−0.00625cm−1.1/f=(1.50/1.60-1)(0.10)=-0.00625\,\mathrm{cm^{-1}}.f=−160cmdiverging in the higher-index surrounding medium.\boxed{f=-160\,\mathrm{cm}}\quad\text{diverging in the higher-index surrounding medium}.

Physical check

Lens shape alone does not determine convergence; the refractive-index contrast controls the sign of the power.