Spherical Mirrors — Question 8

Section 34-3 · Physics pages 5606–5607

Question 8 Placing a source at the paraxial focus makes outgoing slopes vanish A paraxial source is on the axis a positive distance p in front of a concave mirror of radius R. A ray hits at height h. To first order, its incident angle is h/p and the normal tilt is h/R. Measure outgoing slope relative to distance increasing away from the mirror. F C V Schematic; labels, not drawing lengths, specify the data. (a) Use reflection to obtain the outgoing slope and find the source distance producing collimation. (b) If p is slightly displaced from f=R/2 by delta, derive the first-order residual slope.
Show solutionHide solution
Question 8 - Solution Placing a source at the paraxial focus makes outgoing slopes vanish F C V (a) Method and calculation uout = h/p −2h/R = h(1/p −1/f) . uout = 0 for all h ⇒p = f = R/2 . (b) Interpretation and further calculation p = f + δ : 1/p ≃1/f −δ/f2. uout ≃−hδ/f2 . Physical check A source farther than the focus gives a negative slope for an upper ray, so the reflected bundle converges.

Question 8

Placing a source at the paraxial focus makes outgoing slopes vanish

A paraxial source is on the axis a positive distance p in front of a concave mirror of radius R. A ray hits at height h. To first order, its incident angle is h/p and the normal tilt is h/R. Measure outgoing slope relative to distance increasing away from the mirror.

Diagram shown in the original SVG worksheet.

  1. Use reflection to obtain the outgoing slope and find the source distance producing collimation.

  2. If p is slightly displaced from f=R/2 by delta, derive the first-order residual slope.

Question 8 - Solution

Placing a source at the paraxial focus makes outgoing slopes vanish

Diagram shown in the original SVG worksheet.

(a) Method and calculation

uout=h/p−2h/R=h(1/p−1/f).\boxed{u_{\mathrm{out}}=h/p-2h/R=h(1/p-1/f)}.uout=0for all h⇒p=f=R/2.u_{\mathrm{out}}=0\ \text{for all }h\Rightarrow\boxed{p=f=R/2}.

(b) Interpretation and further calculation

p=f+δ:1/p≃1/f−δ/f2.p=f+\delta:\quad1/p\simeq1/f-\delta/f^2.uout≃−hδ/f2.\boxed{u_{\mathrm{out}}\simeq-h\delta/f^2}.

Physical check

A source farther than the focus gives a negative slope for an upper ray, so the reflected bundle converges.