Spherical Mirrors — Question 6

Section 34-3 · Physics pages 5602–5603

Question 6 Transverse spherical aberration grows cubically with aperture height At the paraxial focal plane of a concave sphere, an exact ray at polar angle theta has signed height yF = R sin θ(cos θ −1)/ cos 2θ. Use small-angle expansions and ray height h=R sin(theta). Neglect diffraction. h |yF | Schematic; labels, not drawing lengths, specify the data. (a) Find the leading transverse error in terms of h and R. (b) If the aperture radius is halved, find the leading change in edge-ray blur radius and the collected power for uniform illumination.
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Question 6 - Solution Transverse spherical aberration grows cubically with aperture height h |yF | (a) Method and calculation sin θ ≃θ, cos θ −1 ≃−θ2/2, cos 2θ ≃1. yF ≃−Rθ3/2 ≃−h3/(2R2) . (b) Interpretation and further calculation bedge(a/2)/bedge(a) ≃(1/2)3 = 1/8 . P ∝πa2 ⇒P(a/2)/P(a) = 1/4 . Physical check Stopping down sharply reduces geometrical spherical aberration, at the cost of collected light; diffraction eventually matters for small apertures.

Question 6

Transverse spherical aberration grows cubically with aperture height

At the paraxial focal plane of a concave sphere, an exact ray at polar angle theta has signed height yF=Rsin⁡θ(cos⁡θ−1)/cos⁡2θy_F=R\sin\theta(\cos\theta-1)/\cos2\theta. Use small-angle expansions and ray height h=R sin(theta). Neglect diffraction.

Diagram shown in the original SVG worksheet.

  1. Find the leading transverse error in terms of h and R.

  2. If the aperture radius is halved, find the leading change in edge-ray blur radius and the collected power for uniform illumination.

Question 6 - Solution

Transverse spherical aberration grows cubically with aperture height

Diagram shown in the original SVG worksheet.

(a) Method and calculation

sin⁡θ≃θ,cos⁡θ−1≃−θ2/2,cos⁡2θ≃1.\sin\theta\simeq\theta,\quad\cos\theta-1\simeq-\theta^2/2,\quad\cos2\theta\simeq1.yF≃−Rθ3/2≃−h3/(2R2).\boxed{y_F\simeq-R\theta^3/2\simeq-h^3/(2R^2)}.

(b) Interpretation and further calculation

bedge(a/2)/bedge(a)≃(1/2)3=1/8.\boxed{b_{\mathrm{edge}}(a/2)/b_{\mathrm{edge}}(a)\simeq(1/2)^3=1/8}.P∝πa2⇒P(a/2)/P(a)=1/4.P\propto\pi a^2\Rightarrow\boxed{P(a/2)/P(a)=1/4}.

Physical check

Stopping down sharply reduces geometrical spherical aberration, at the cost of collected light; diffraction eventually matters for small apertures.