Spherical Mirrors — Question 4

Section 34-3 · Physics pages 5598–5599

Question 4 An exact spherical ray intercept depends on ray height A concave spherical mirror has vertex at x=0 and center at x=-R, with R positive. A parallel ray travels in +x and strikes at xP = −R + R cos θ, yP = R sin θ, with zero less than theta less than 45 degrees. Reflection gives direction (−cos 2θ, −sin 2θ). F C V Schematic; labels, not drawing lengths, specify the data. (a) Find the axial intersection coordinate of the reflected ray. (b) Express its positive vertex distance q(theta) and take the paraxial limit.
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Question 4 - Solution An exact spherical ray intercept depends on ray height F C V (a) Method and calculation xI = xP −yP cot 2θ = −R + R cos θ −R sin θ cot 2θ. cos θ −sin θ cot 2θ = 1/(2 cos θ) ⇒xI = −R + R/(2 cos θ) . (b) Interpretation and further calculation q(θ) = −xI = R[1 −1/(2 cos θ)] . lim θ→0 q(θ) = R/2 = f . Physical check Finite-height rays do not all cross at the paraxial focus; the restriction on theta keeps the reflected ray directed back toward the axis.

Question 4

An exact spherical ray intercept depends on ray height

A concave spherical mirror has vertex at x=0 and center at x=-R, with R positive. A parallel ray travels in +x and strikes at xP=−R+Rcos⁡θx_P=-R+R\cos\theta, yP=Rsin⁡θy_P=R\sin\theta, with zero less than theta less than 45 degrees. Reflection gives direction (−cos⁡2θ,−sin⁡2θ)(-\cos2\theta,-\sin2\theta).

Diagram shown in the original SVG worksheet.

  1. Find the axial intersection coordinate of the reflected ray.

  2. Express its positive vertex distance q(theta) and take the paraxial limit.

Question 4 - Solution

An exact spherical ray intercept depends on ray height

Diagram shown in the original SVG worksheet.

(a) Method and calculation

xI=xP−yPcot⁡2θ=−R+Rcos⁡θ−Rsin⁡θcot⁡2θ.x_I=x_P-y_P\cot2\theta=-R+R\cos\theta-R\sin\theta\cot2\theta.cos⁡θ−sin⁡θcot⁡2θ=1/(2cos⁡θ)⇒xI=−R+R/(2cos⁡θ).\cos\theta-\sin\theta\cot2\theta=1/(2\cos\theta)\Rightarrow\boxed{x_I=-R+R/(2\cos\theta)}.

(b) Interpretation and further calculation

q(θ)=−xI=R[1−1/(2cos⁡θ)].\boxed{q(\theta)=-x_I=R[1-1/(2\cos\theta)]}.limθ→0q(θ)=R/2=f.\boxed{\lim_{\theta\to0}q(\theta)=R/2=f}.

Physical check

Finite-height rays do not all cross at the paraxial focus; the restriction on theta keeps the reflected ray directed back toward the axis.