Plane Mirrors — Question 10

Section 34-2 · Physics pages 5590–5591

Question 10 A sixty-degree mirror wedge generates a finite orbit of image points Two ideal plane mirrors meet at 60 degrees. A point object lies at polar angle 20 degrees between them, at radius r from their intersection. In the cross section, reflections in the two mirror lines map an angle theta to -theta and to 120 degrees minus theta. O Schematic; labels, not drawing lengths, specify the data. (a) Generate all distinct angular positions in the orbit under repeated reflections. (b) Count the images excluding the object, and identify why no new positions arise after three ordered pairs of reflections.
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Question 10 - Solution A sixty-degree mirror wedge generates a finite orbit of image points O (a) Method and calculation S60S0(θ) = 120◦+ θ (mod 360◦). θ ∈{20◦, 100◦, 140◦, 220◦, 260◦, 340◦} . (b) Interpretation and further calculation Nimages = 6 −1 = 5 . (S60S0)3(θ) = θ + 360◦≡θ . Physical check All orbit points remain at radius r; the 20-degree object is not on a mirror or a symmetry axis that would merge positions.

Question 10

A sixty-degree mirror wedge generates a finite orbit of image points

Two ideal plane mirrors meet at 60 degrees. A point object lies at polar angle 20 degrees between them, at radius r from their intersection. In the cross section, reflections in the two mirror lines map an angle theta to -theta and to 120 degrees minus theta.

Diagram shown in the original SVG worksheet.

  1. Generate all distinct angular positions in the orbit under repeated reflections.

  2. Count the images excluding the object, and identify why no new positions arise after three ordered pairs of reflections.

Question 10 - Solution

A sixty-degree mirror wedge generates a finite orbit of image points

Diagram shown in the original SVG worksheet.

(a) Method and calculation

S60S0(θ)=120∘+θ(mod⁡360∘).S_{60}S_0(\theta)=120^\circ+\theta\pmod{360^\circ}.θ∈{20∘,100∘,140∘,220∘,260∘,340∘}.\boxed{\theta\in\{20^\circ,100^\circ,140^\circ,220^\circ,260^\circ,340^\circ\}}.

(b) Interpretation and further calculation

Nimages=6−1=5.\boxed{N_{\mathrm{images}}=6-1=5}.(S60S0)3(θ)=θ+360∘≡θ.(S_{60}S_0)^3(\theta)=\theta+360^\circ\equiv\boxed{\theta}.

Physical check

All orbit points remain at radius r; the 20-degree object is not on a mirror or a symmetry axis that would merge positions.