Plane Mirrors — Question 7

Section 34-2 · Physics pages 5584–5585

Question 7 Two parallel reflections translate an image by twice the mirror separation Two ideal plane mirrors have coordinates x=0 and x=L. An object lies at x=a with zero less than a less than L. Reflection maps are S0(x) = −x and SL(x) = 2L −x. a L successive images Schematic; labels, not drawing lengths, specify the data. (a) Find the image coordinate after reflection first at x=0 and then at x=L, and after the reverse order. (b) Find the coordinate after N repetitions of the first ordered pair and its displacement from the original object.
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Question 7 - Solution Two parallel reflections translate an image by twice the mirror separation a L successive images (a) Method and calculation SL[S0(a)] = 2L + a . S0[SL(a)] = a −2L . (b) Interpretation and further calculation (SLS0)N(a) = a + 2NL . ∆xN = 2NL . Physical check The two ordered compositions are opposite translations; image order matters even though each individual reflection is its own inverse.

Question 7

Two parallel reflections translate an image by twice the mirror separation

Two ideal plane mirrors have coordinates x=0 and x=L. An object lies at x=a with zero less than a less than L. Reflection maps are S0(x)=−xS_0(x)=-x and SL(x)=2L−xS_L(x)=2L-x.

Diagram shown in the original SVG worksheet.

  1. Find the image coordinate after reflection first at x=0 and then at x=L, and after the reverse order.

  2. Find the coordinate after N repetitions of the first ordered pair and its displacement from the original object.

Question 7 - Solution

Two parallel reflections translate an image by twice the mirror separation

Diagram shown in the original SVG worksheet.

(a) Method and calculation

SL[S0(a)]=2L+a.\boxed{S_L[S_0(a)]=2L+a}.S0[SL(a)]=a−2L.\boxed{S_0[S_L(a)]=a-2L}.

(b) Interpretation and further calculation

(SLS0)N(a)=a+2NL.(S_LS_0)^N(a)=\boxed{a+2NL}.ΔxN=2NL.\boxed{\Delta x_N=2NL}.

Physical check

The two ordered compositions are opposite translations; image order matters even though each individual reflection is its own inverse.