Two Types of Image — Question 10

Section 34-1 · Physics pages 5570–5571

Question 10 A pinhole forms a real image without focusing by refraction or reflection An object arrow of height h stands distance p before a small pinhole. A screen is distance q behind the hole. Light travels in straight lines; the hole is small enough to neglect geometrical blur, and diffraction is excluded. h Schematic; labels, not drawing lengths, specify the data. (a) Derive the signed image height from similar triangles and classify the image. (b) For p=1.2 m, q=0.18 m, and h=0.20 m, find image height and the screen distance needed to double its magnitude.
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Question 10 - Solution A pinhole forms a real image without focusing by refraction or reflection h (a) Method and calculation hI q = −h p ⇒hI = −qh/p, m = −q/p . real, inverted image on the screen . (b) Interpretation and further calculation hI = −0.18(0.20)/1.2 = −0.030 m . |hI| ∝q ⇒qnew = 0.36 m . Physical check The pinhole selects narrow bundles instead of redirecting them. Image formation and optical focusing are not identical operations.

Question 10

A pinhole forms a real image without focusing by refraction or reflection

An object arrow of height h stands distance p before a small pinhole. A screen is distance q behind the hole. Light travels in straight lines; the hole is small enough to neglect geometrical blur, and diffraction is excluded.

Diagram shown in the original SVG worksheet.

  1. Derive the signed image height from similar triangles and classify the image.

  2. For p=1.2 m, q=0.18 m, and h=0.20 m, find image height and the screen distance needed to double its magnitude.

Question 10 - Solution

A pinhole forms a real image without focusing by refraction or reflection

Diagram shown in the original SVG worksheet.

(a) Method and calculation

hIq=−hp⇒hI=−qh/p,m=−q/p.\frac{h_I}{q}=-\frac{h}{p}\Rightarrow\boxed{h_I=-qh/p,\quad m=-q/p}.real, inverted image on the screen.\boxed{\text{real, inverted image on the screen}}.

(b) Interpretation and further calculation

hI=−0.18(0.20)/1.2=−0.030m.\boxed{h_I=-0.18(0.20)/1.2=-0.030\,\mathrm m}.|hI|∝q⇒qnew=0.36m.|h_I|\propto q\Rightarrow\boxed{q_{\mathrm{new}}=0.36\,\mathrm m}.

Physical check

The pinhole selects narrow bundles instead of redirecting them. Image formation and optical focusing are not identical operations.