Two Types of Image — Question 7

Section 34-1 · Physics pages 5564–5565

Question 7 A converging incident bundle supplies a virtual object to a later element Before reaching a second optical element at x=0, rays travel in +x and would meet at x=12 cm if that element were removed. Define its object distance p positive for an object on the incoming side. With the element present, outgoing rays meet at x=30 cm. Ov I Schematic; labels, not drawing lengths, specify the data. (a) Assign the signed object and image distances for the second element. (b) Classify its object and image, and calculate the change in the convergence coordinate caused by insertion.
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Question 7 - Solution A converging incident bundle supplies a virtual object to a later element Ov I (a) Method and calculation xO,would be = +12 cm ⇒p = −12 cm . xI,actual = +30 cm ⇒q = +30 cm . (b) Interpretation and further calculation virtual object; real image . ∆x = 30 −12 = 18 cm farther downstream. Physical check The incoming rays do not originate from the virtual object point; they are already converging toward it when intercepted.

Question 7

A converging incident bundle supplies a virtual object to a later element

Before reaching a second optical element at x=0, rays travel in +x and would meet at x=12 cm if that element were removed. Define its object distance p positive for an object on the incoming side. With the element present, outgoing rays meet at x=30 cm.

Diagram shown in the original SVG worksheet.

  1. Assign the signed object and image distances for the second element.

  2. Classify its object and image, and calculate the change in the convergence coordinate caused by insertion.

Question 7 - Solution

A converging incident bundle supplies a virtual object to a later element

Diagram shown in the original SVG worksheet.

(a) Method and calculation

xO,wouldbe=+12cm⇒p=−12cm.x_{O,\mathrm{would\ be}}=+12\,\mathrm{cm}\Rightarrow\boxed{p=-12\,\mathrm{cm}}.xI,actual=+30cm⇒q=+30cm.x_{I,\mathrm{actual}}=+30\,\mathrm{cm}\Rightarrow\boxed{q=+30\,\mathrm{cm}}.

(b) Interpretation and further calculation

virtual object; real image.\boxed{\text{virtual object; real image}}.Δx=30−12=18cmfarther downstream.\boxed{\Delta x=30-12=18\,\mathrm{cm}}\quad\text{farther downstream}.

Physical check

The incoming rays do not originate from the virtual object point; they are already converging toward it when intercepted.