Reflection and Refraction — Question 9

Section 33-7 · Physics pages 5508–5509

Question 9 Weak dispersion changes the refracted angle with a calculable sensitivity A beam enters a transparent material from air at fixed incidence angle i. The index changes from n to n plus a small delta n between two colors. The refracted angle is r, measured from the normal. n2 n1 normal Schematic; labels, not drawing lengths, specify the data. (a) Differentiate Snells law to obtain the first-order change in r. (b) For n=1.50, r=30 degrees, and delta n=0.010, estimate the angular change in radians and degrees.
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Question 9 - Solution Weak dispersion changes the refracted angle with a calculable sensitivity n2 n1 normal (a) Method and calculation sin i = n sin r ⇒0 = sin r dn + n cos r dr. dr = −tan r n dn . (b) Interpretation and further calculation ∆r ≃−tan 30◦ 1.50 (0.010) = −3.84900 × 10−3 rad . ∆r ≃−0.220532◦. Physical check The higher-index color bends closer to the normal; this derivative holds at fixed incident angle.

Question 9

Weak dispersion changes the refracted angle with a calculable sensitivity

A beam enters a transparent material from air at fixed incidence angle i. The index changes from n to n plus a small delta n between two colors. The refracted angle is r, measured from the normal.

Diagram shown in the original SVG worksheet.

  1. Differentiate Snells law to obtain the first-order change in r.

  2. For n=1.50, r=30 degrees, and delta n=0.010, estimate the angular change in radians and degrees.

Question 9 - Solution

Weak dispersion changes the refracted angle with a calculable sensitivity

Diagram shown in the original SVG worksheet.

(a) Method and calculation

sin⁡i=nsin⁡r⇒0=sin⁡rdn+ncos⁡rdr.\sin i=n\sin r\Rightarrow0=\sin r\,dn+n\cos r\,dr.dr=−tan⁡rndn.\boxed{dr=-\frac{\tan r}{n}\,dn}.

(b) Interpretation and further calculation

Δr≃−tan⁡30∘1.50(0.010)=−3.84900×10−3rad.\Delta r\simeq-\frac{\tan30^\circ}{1.50}(0.010)=\boxed{-3.84900\times10^{-3}\,\mathrm{rad}}.Δr≃−0.220532∘.\boxed{\Delta r\simeq-0.220532^\circ}.

Physical check

The higher-index color bends closer to the normal; this derivative holds at fixed incident angle.