Polarization — Question 9

Section 33-6 · Physics pages 5488–5489

Question 9 Incoherent orthogonal beams and a circular wave share linear-analyzer readings Compare two beams of the same total intensity I0: beam A is an equal incoherent mixture of x and y linear polarization; beam B is a coherent circular wave. Only an ideal linear analyzer is initially available. quarter-wave plate analyzer Schematic; labels, not drawing lengths, specify the data. (a) Show that neither beam varies in transmitted intensity as the analyzer rotates. (b) Place a quarter-wave plate before the analyzer, with a phase delay chosen to convert beam B to linear polarization. Find the maximum and minimum readings for each beam.
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Question 9 - Solution Incoherent orthogonal beams and a circular wave share linear-analyzer readings quarter-wave plate analyzer (a) Method and calculation IA(θ) = 1 2I0 cos2 θ + 1 2I0 sin2 θ = I0/2. IB(θ) = I0/2 for all θ . (b) Interpretation and further calculation IA,max = IA,min = I0/2 after the plate. IB,max = I0, IB,min = 0 after conversion to linear. Physical check A phase plate cannot create coherence between the independent components of A; it can change the relative phase of coherent B.

Question 9

Incoherent orthogonal beams and a circular wave share linear-analyzer readings

Compare two beams of the same total intensity I0: beam A is an equal incoherent mixture of x and y linear polarization; beam B is a coherent circular wave. Only an ideal linear analyzer is initially available.

Diagram shown in the original SVG worksheet.

  1. Show that neither beam varies in transmitted intensity as the analyzer rotates.

  2. Place a quarter-wave plate before the analyzer, with a phase delay chosen to convert beam B to linear polarization. Find the maximum and minimum readings for each beam.

Question 9 - Solution

Incoherent orthogonal beams and a circular wave share linear-analyzer readings

Diagram shown in the original SVG worksheet.

(a) Method and calculation

IA(θ)=12I0cos⁡2θ+12I0sin⁡2θ=I0/2.I_A(\theta)=\tfrac12I_0\cos^2\theta+\tfrac12I_0\sin^2\theta=I_0/2.IB(θ)=I0/2for allθ.\boxed{I_B(\theta)=I_0/2\quad\text{for all}\ \theta}.

(b) Interpretation and further calculation

IA,max=IA,min=I0/2after the plate.\boxed{I_{A,\max}=I_{A,\min}=I_0/2}\quad\text{after the plate}.IB,max=I0,IB,min=0after conversion to linear.\boxed{I_{B,\max}=I_0,\quad I_{B,\min}=0}\quad\text{after conversion to linear}.

Physical check

A phase plate cannot create coherence between the independent components of A; it can change the relative phase of coherent B.