Polarization — Question 5

Section 33-6 · Physics pages 5480–5481

Question 5 A finite extinction ratio leaves residual light through a crossed pair Two identical imperfect linear polarizers transmit intensity fractions a=0.90 and b=0.01 along their principal and perpendicular axes, with no mixing. Unpolarized intensity I0 enters the pair. first rotate second Schematic; labels, not drawing lengths, specify the data. (a) Find the intensity and degree of linear polarization after the first element. (b) Find the final intensity for parallel and crossed axes and their ratio.
Show solutionHide solution
Question 5 - Solution A finite extinction ratio leaves residual light through a crossed pair first rotate second (a) Method and calculation I1 = I0(a + b)/2 = 0.455I0 . PL = (a −b)/(a + b) = 89/91 = 0.97802 . (b) Interpretation and further calculation I∥= I0(a2 + b2)/2 = 0.40505I0, I⊥= I0ab = 0.009I0 . I∥/I⊥= (a2 + b2)/(2ab) = 45.0056 . Physical check The two incoherent orthogonal components must be tracked separately through both elements.

Question 5

A finite extinction ratio leaves residual light through a crossed pair

Two identical imperfect linear polarizers transmit intensity fractions a=0.90 and b=0.01 along their principal and perpendicular axes, with no mixing. Unpolarized intensity I0 enters the pair.

Diagram shown in the original SVG worksheet.

  1. Find the intensity and degree of linear polarization after the first element.

  2. Find the final intensity for parallel and crossed axes and their ratio.

Question 5 - Solution

A finite extinction ratio leaves residual light through a crossed pair

Diagram shown in the original SVG worksheet.

(a) Method and calculation

I1=I0(a+b)/2=0.455I0.I_1=I_0(a+b)/2=\boxed{0.455I_0}.𝒫L=(a−b)/(a+b)=89/91=0.97802.\boxed{\mathcal P_L=(a-b)/(a+b)=89/91=0.97802}.

(b) Interpretation and further calculation

I∥=I0(a2+b2)/2=0.40505I0,I⟂=I0ab=0.009I0.\boxed{I_{\parallel}=I_0(a^2+b^2)/2=0.40505I_0,\quad I_{\perp}=I_0ab=0.009I_0}.I∥/I⟂=(a2+b2)/(2ab)=45.0056.\boxed{I_{\parallel}/I_{\perp}=(a^2+b^2)/(2ab)=45.0056}.

Physical check

The two incoherent orthogonal components must be tracked separately through both elements.