Radiation Pressure — Question 1

Section 33-5 · Physics pages 5452–5453

Question 1 A partly transmitting foil separates heating from momentum transfer A normally incident vacuum beam carries 12 W. A stationary foil reflects fraction R=0.65, transmits T=0.20 forward, and absorbs the remainder. Both surrounding regions are vacuum; use c=3.00 times 10 to the eighth m/s. I area A Schematic; labels, not drawing lengths, specify the data. (a) Find the force from incoming minus outgoing momentum flux. (b) Find the heating rate and compare the force with that of a perfect absorber receiving the same power.
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Question 1 - Solution A partly transmitting foil separates heating from momentum transfer I area A (a) Method and calculation F = P c − (TP c −RP c ) = (1 + R −T)P c . F = 5.80 × 10−8 N . (b) Interpretation and further calculation A = 1 −R −T = 0.15, ˙Q = AP = 1.80 W . Fabs = P/c = 4.00 × 10−8 N, F/Fabs = 1.45 . Physical check Reflection transfers momentum without depositing the corresponding optical energy as heat in the stationary idealization.

Question 1

A partly transmitting foil separates heating from momentum transfer

A normally incident vacuum beam carries 12 W. A stationary foil reflects fraction R=0.65, transmits T=0.20 forward, and absorbs the remainder. Both surrounding regions are vacuum; use c=3.00 times 10 to the eighth m/s.

Diagram shown in the original SVG worksheet.

  1. Find the force from incoming minus outgoing momentum flux.

  2. Find the heating rate and compare the force with that of a perfect absorber receiving the same power.

Question 1 - Solution

A partly transmitting foil separates heating from momentum transfer

Diagram shown in the original SVG worksheet.

(a) Method and calculation

F=Pc−(TPc−RPc)=(1+R−T)Pc.F=\frac{P}{c}-\left(\frac{TP}{c}-\frac{RP}{c}\right)=\frac{(1+R-T)P}{c}.F=5.80×10−8N.\boxed{F=5.80\times10^{-8}\,\mathrm N}.

(b) Interpretation and further calculation

𝒜=1−R−T=0.15,Q̇=𝒜P=1.80W.\mathcal A=1-R-T=0.15,\quad\boxed{\dot Q=\mathcal AP=1.80\,\mathrm W}.Fabs=P/c=4.00×10−8N,F/Fabs=1.45.F_{\mathrm{abs}}=P/c=4.00\times10^{-8}\,\mathrm N,\quad\boxed{F/F_{\mathrm{abs}}=1.45}.

Physical check

Reflection transfers momentum without depositing the corresponding optical energy as heat in the stationary idealization.