Energy Transport and the Poynting Vector — Question 9

Section 33-4 · Physics pages 5448–5449

Question 9 The Poynting flux in a coaxial cable reproduces electrical power An ideal vacuum-filled coaxial line has inner radius a and outer radius b, voltage V, and current I in +z on the inner conductor. In the dielectric region use Er = V/[r ln(b/a)] and Bϕ = µ0I/(2πr). Er Bϕ Sz out of page Schematic; labels, not drawing lengths, specify the data. (a) Find the Poynting vector between the conductors. (b) Integrate its axial flux over the annular cross section and compare with circuit power.
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Question 9 - Solution The Poynting flux in a coaxial cable reproduces electrical power Er Bϕ Sz out of page (a) Method and calculation ˆr × ˆϕ = ˆz ⇒S = ErBϕ µ0 ˆz. S = V I 2πr2 ln(b/a) ˆz . (b) Interpretation and further calculation P = ∫b a Sz2πr dr = V I ln(b/a) ∫b a dr r . P = V I . Physical check The energy flows through the field-filled annulus; the Poynting vector is not limited to freely propagating radiation in empty space.

Question 9

The Poynting flux in a coaxial cable reproduces electrical power

An ideal vacuum-filled coaxial line has inner radius a and outer radius b, voltage V, and current I in +z on the inner conductor. In the dielectric region use Er=V/[rln⁡(b/a)]E_r=V/[r\ln(b/a)] and Bϕ=μ0I/(2πr)B_\phi=\mu_0I/(2\pi r).

Diagram shown in the original SVG worksheet.

  1. Find the Poynting vector between the conductors.

  2. Integrate its axial flux over the annular cross section and compare with circuit power.

Question 9 - Solution

The Poynting flux in a coaxial cable reproduces electrical power

Diagram shown in the original SVG worksheet.

(a) Method and calculation

r̂×ϕ̂=ẑ⇒𝑺=ErBϕμ0ẑ.\hat r\times\hat\phi=\hat z\Rightarrow\mathbf S=\frac{E_rB_\phi}{\mu_0}\hat z.𝑺=VI2πr2ln⁡(b/a)ẑ.\boxed{\mathbf S=\frac{VI}{2\pi r^2\ln(b/a)}\hat z}.

(b) Interpretation and further calculation

P=∫abSz2πrdr=VIln⁡(b/a)∫abdrr.P=\int_a^b S_z2\pi r\,dr=\frac{VI}{\ln(b/a)}\int_a^b\frac{dr}{r}.P=VI.\boxed{P=VI}.

Physical check

The energy flows through the field-filled annulus; the Poynting vector is not limited to freely propagating radiation in empty space.