Energy Transport and the Poynting Vector — Question 5

Section 33-4 · Physics pages 5440–5441

Question 5 Coherent field addition can change the intensity without changing either input amplitude Two co-propagating vacuum waves share polarization and electric amplitude E0. Their phase difference is delta. Each alone has intensity I1 = ϵ0cE2 0/2. x E c two coherent fields; phase offset δ Schematic; labels, not drawing lengths, specify the data. (a) Derive the combined intensity as a function of delta. (b) Find it at delta=0, pi/2, and pi. Then find the mean intensity if delta is uniformly randomized over a full cycle.
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Question 5 - Solution Coherent field addition can change the intensity without changing either input amplitude x E c two coherent fields; phase offset δ (a) Method and calculation E = E0[cos ϕ + cos(ϕ + δ)] = 2E0 cos(δ/2) cos(ϕ + δ/2). I = 4I1 cos2(δ/2) = 2I1(1 + cos δ) . (b) Interpretation and further calculation I(0) = 4I1, I(π/2) = 2I1, I(π) = 0 . ⟨cos δ⟩δ = 0 ⇒⟨I⟩δ = 2I1 . Physical check The cross term survives only when relative phase is controlled; simple intensity addition assumes it averages away.

Question 5

Coherent field addition can change the intensity without changing either input amplitude

Two co-propagating vacuum waves share polarization and electric amplitude E0. Their phase difference is delta. Each alone has intensity I1=ϵ0cE02/2I_1=\epsilon_0cE_0^2/2.

Diagram shown in the original SVG worksheet.

  1. Derive the combined intensity as a function of delta.

  2. Find it at delta=0, pi/2, and pi. Then find the mean intensity if delta is uniformly randomized over a full cycle.

Question 5 - Solution

Coherent field addition can change the intensity without changing either input amplitude

Diagram shown in the original SVG worksheet.

(a) Method and calculation

E=E0[cos⁡ϕ+cos⁡(ϕ+δ)]=2E0cos⁡(δ/2)cos⁡(ϕ+δ/2).E=E_0[\cos\phi+\cos(\phi+\delta)]=2E_0\cos(\delta/2)\cos(\phi+\delta/2).I=4I1cos⁡2(δ/2)=2I1(1+cos⁡δ).\boxed{I=4I_1\cos^2(\delta/2)=2I_1(1+\cos\delta)}.

(b) Interpretation and further calculation

I(0)=4I1,I(π/2)=2I1,I(π)=0.\boxed{I(0)=4I_1,\quad I(\pi/2)=2I_1,\quad I(\pi)=0}.⟨cos⁡δ⟩δ=0⇒⟨I⟩δ=2I1.\langle\cos\delta\rangle_\delta=0\Rightarrow\boxed{\langle I\rangle_\delta=2I_1}.

Physical check

The cross term survives only when relative phase is controlled; simple intensity addition assumes it averages away.