The Traveling Electromagnetic Wave, Qualitatively — Question 10

Section 33-2 · Physics pages 5410–5411

Question 10 A faster temporal oscillation requires a proportionally shorter vacuum wavelength Two sinusoidal vacuum plane waves have equal electric amplitudes and frequencies f and 3f. Each travels along +x with the same polarization. Compare them at equal phase. x E c Schematic; labels, not drawing lengths, specify the data. (a) Compare their periods, wavelengths, wave numbers, and magnetic amplitudes. (b) Compare maximum time derivatives and maximum spatial derivatives of E. Explain how both derivative changes preserve the propagation speed.
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Question 10 - Solution A faster temporal oscillation requires a proportionally shorter vacuum wavelength x E c (a) Method and calculation T2/T1 = 1/3, λ2/λ1 = 1/3, k2/k1 = 3 . B0 = E0/c ⇒B02/B01 = 1 . (b) Interpretation and further calculation |∂tE|max = ωE0, |∂xE|max = kE0 ⇒both ratios = 3 . |∂tE|max |∂xE|max = ω/k = c for both . Physical check Greater frequency changes the space and time scales together; it does not require a larger field amplitude.

Question 10

A faster temporal oscillation requires a proportionally shorter vacuum wavelength

Two sinusoidal vacuum plane waves have equal electric amplitudes and frequencies f and 3f. Each travels along +x with the same polarization. Compare them at equal phase.

Diagram shown in the original SVG worksheet.

  1. Compare their periods, wavelengths, wave numbers, and magnetic amplitudes.

  2. Compare maximum time derivatives and maximum spatial derivatives of E. Explain how both derivative changes preserve the propagation speed.

Question 10 - Solution

A faster temporal oscillation requires a proportionally shorter vacuum wavelength

Diagram shown in the original SVG worksheet.

(a) Method and calculation

T2/T1=1/3,λ2/λ1=1/3,k2/k1=3.\boxed{T_2/T_1=1/3,\quad\lambda_2/\lambda_1=1/3,\quad k_2/k_1=3}.B0=E0/c⇒B02/B01=1.B_0=E_0/c\Rightarrow\boxed{B_{02}/B_{01}=1}.

(b) Interpretation and further calculation

|∂tE|max=ωE0,|∂xE|max=kE0⇒both ratios=3.|\partial_tE|_{\max}=\omega E_0,\quad|\partial_xE|_{\max}=kE_0\Rightarrow\boxed{\text{both ratios}=3}.|∂tE|max|∂xE|max=ω/k=c for both.\boxed{\frac{|\partial_tE|_{\max}}{|\partial_xE|_{\max}}=\omega/k=c\text{ for both}}.

Physical check

Greater frequency changes the space and time scales together; it does not require a larger field amplitude.